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Nov
16
comment Prove that $\mathbb Q(3+i) = \mathbb Q(1-i)$.
Thank you! This was embarrassingly easy in hindsight, but I just kind of got thrown into this lesson and the book I'm using is extremely unclear. Out of curiosity, is it a degree two extension because every number can be expressed with factors of {1,i} which has two elements? Or is it because i is the solution to x^2 + 1 = 0, and that's a degree two polynomial? Sorry if I'm compounding my earlier question with another dumb question, but I'm pretty much flying blind here.
Nov
16
awarded  Student
Nov
16
asked Prove that $\mathbb Q(3+i) = \mathbb Q(1-i)$.