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  • 0 posts edited
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  • 115 votes cast
Jul
29
asked Binary to Decimal
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
@ByronSchmuland oh! this because I partially copied from linked question, Now corrected. Thanks :)
Jun
10
revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
edited body
Jun
10
accepted How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
ok So you updated your answer.. its correct na Thanks a lot vonbrand!
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
@MarkBennet Got it!..done thanks :)
Jun
10
revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
added 4 characters in body
Jun
10
revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
edited body
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
@MarkBennet Please check my answer
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
Please check my answer ..
Jun
10
answered How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
Hi please read Edit part its actually: (1*2) + (3*2) + (4*3) + (5*4) + (6*5) + ... + (N * (N+1)) Sorry I mistake I made
Jun
10
revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
added 193 characters in body
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
@MarkBennet Got it Thanks!!, But I am sure for my final sequence (1*2) + (3*2) + (4*3) + (5*4) + (6*5) + ... + (N * (N-1))
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
do you means (1*2) + (3*2) + (4*3) + (5*4) + (6*5) + ... + (N * (N-1)) ? by last description
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
@MarkBennet 6 is absent in series
Jun
10
comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
I am tiring to answer some other problem related to computer science (I am from computer so its hard to solve me I was trying since an hours). Can someone also improve my tags
Jun
10
asked How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N?
May
14
awarded  Caucus
Apr
2
comment Is 1+1 =2 a theorem?
Ittay Weiss .. nice answer !!