Grijesh Chauhan
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218
Next privilege 250 Rep.
 Jul 29 asked Binary to Decimal Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? @ByronSchmuland oh! this because I partially copied from linked question, Now corrected. Thanks :) Jun 10 revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? edited body Jun 10 accepted How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? ok So you updated your answer.. its correct na Thanks a lot vonbrand! Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? @MarkBennet Got it!..done thanks :) Jun 10 revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? added 4 characters in body Jun 10 revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? edited body Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? @MarkBennet Please check my answer Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? Please check my answer .. Jun 10 answered How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? Hi please read Edit part its actually: (1*2) + (3*2) + (4*3) + (5*4) + (6*5) + ... + (N * (N+1)) Sorry I mistake I made Jun 10 revised How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? added 193 characters in body Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? @MarkBennet Got it Thanks!!, But I am sure for my final sequence (1*2) + (3*2) + (4*3) + (5*4) + (6*5) + ... + (N * (N-1)) Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? do you means (1*2) + (3*2) + (4*3) + (5*4) + (6*5) + ... + (N * (N-1)) ? by last description Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? @MarkBennet 6 is absent in series Jun 10 comment How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? I am tiring to answer some other problem related to computer science (I am from computer so its hard to solve me I was trying since an hours). Can someone also improve my tags Jun 10 asked How to simplify summation $(1\cdot2) + (2\cdot3) + (3\cdot4) + (4\cdot5) + (5\cdot6) + … + (N\cdot(N+1))$ in terms of N? May 14 awarded Caucus Apr 2 comment Is 1+1 =2 a theorem? Ittay Weiss .. nice answer !!