meta user
network profile
| bio | website | blog.sina.com.cn/strongart |
|---|---|---|
| location | China | |
| age | ||
| visits | member for | 2 years, 5 months |
| seen | yesterday | |
| stats | profile views | 931 |
如果你懂中文的话，欢迎访问我的博客（Website ）。
I study maths by myself，lack the papers and any other help，no university ask me to do some research or even help their fool students.Now I am making some lectures of Communicative algebra and some others topics at my blog and other video websites.
But some Chinese maths forums Kill my ID without any reasons and rules,maybe they just ask for exams and homeworks,upload and download some e-books,but I can do some discussing which gives offense to their authority of their organizations and math-leaders.
I think I should make my webname “Strongart” more and more famous because it seems that they like this than mathematics！That is just for some Chinese.
If you have some Chinese friends and students who are really like mathematics and you are also glad to send a letter to him showing that this guy has a little talent in maths,maybe that will become a great help for me.
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Sep 4 |
asked | Compact operators and completely continuous operators |
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Jul 31 |
accepted | Why do we distinguish the continuous spectrum and the residual spectrum? |
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Jul 30 |
comment |
Why do we distinguish the continuous spectrum and the residual spectrum? Yes, it is also true for the norm operator. |
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Jul 30 |
comment |
Why do we distinguish the continuous spectrum and the residual spectrum? Yes, Banach space is the stage. If X is not Banach space, we have another way to break the inverse of λI-T，（λI-T）^(-1) is exist but unbounded, I do not know what is the name for such spectrum. |
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Jul 29 |
comment |
Why do we distinguish the continuous spectrum and the residual spectrum? It seems as we just emphasize this difference for the operator, but not for the Banach algebra, why? |
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Jul 28 |
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Why do we distinguish the continuous spectrum and the residual spectrum? I read the prove again and because of the below bounded condition, we can get the range is closed first,so Ran(T) is the whole space. But I also see some book treat the invertability as one-to-one, a Chinese popular functional analysis book by Gongqing Zhang is an example. |
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Jul 27 |
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Why do we distinguish the continuous spectrum and the residual spectrum? That is from the book "Banach Algebra Techniques in Operator Theory" by Ronald G. Douglas P76.proposition 4.8. Maybe it is because the difference about the definitions. |
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Jul 26 |
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Why do we distinguish the continuous spectrum and the residual spectrum? That is a good reason, but I do not think it is enough. Maybe the following claim is helpful: T is invertible iff T is bounded below and dense range. |
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Jul 25 |
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Why do we distinguish the continuous spectrum and the residual spectrum? Oh, my English is also poor. In fact, I want to know why do we emphasize the "almost surjective" from the "nonsurjective". |
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Jul 24 |
asked | Why do we distinguish the continuous spectrum and the residual spectrum? |
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Jul 13 |
comment |
The Ext functor in the quiver representation Oh,thanks.I have another question about the tilting module:math.stackexchange.com/questions/155187/…, welcome to answer it if it is not too much trouble for you. |
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Jul 13 |
revised |
A question about partial tilting module added 164 characters in body |
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Jul 11 |
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The Ext functor in the quiver representation Oh,I have not realized the A-module before.For the second part,Does λ∈Hom(T(1),T(2))？Maybe it is also not a A-module map,so λ can be nonzero.Am I right? |
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Jul 11 |
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The Ext functor in the quiver representation I see.Thanks for your help. |
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Jul 7 |
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The Ext functor in the quiver representation Thanks,I read this answer many times,but also have some questions.Why there is no hom from T(1) to T(2),as we know,if f∈Hom(M,N),f is not must be onto N.Then we note i to T(i) and get new quiver,also have the arrow λ from 1 to 2,does it means the hom functor from T(1) to T(2)? |
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Jul 6 |
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The Ext functor in the quiver representation Thanks,I realize the start point means the top of the projective module now.For computering τ using 4.2.4,we must computer Nakayama functor first,I know that tne Nakayama functor of P(i) is I(i),but how about the nonprojective module?Some examples in the [ASS] are zero,but I do not think that all the Nakayama functor of nonprojective module are zero. |
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Jul 3 |
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The Ext functor in the quiver representation Thanks,I am think about the following answer.For this part,I am not familiar with the top(discussing in the Lemma 3.2.3),just treat it in a primary way:look for the start point first,then we can express it as the quotient module of the projective module,do it steps by steps,we can use the projective module to express it.Is it also well?But I want to know how to computer the τ, there is not enough information in the 4.4.12,I guess the projective resolution can help to do it,but I do not know how to do this job. |
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Jun 30 |
asked | The exterior product in the Hopf algebra |
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Jun 30 |
accepted | The Ext functor in the quiver representation |
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Jun 30 |
comment |
The Ext functor in the quiver representation For the hom functor,how about the nonzero situation? For example, I cannot understand the forth equation in the Ex6.3.11(a). I need more help the treat the quiver. |
