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 Oct27 awarded Yearling Jul2 awarded Curious Oct27 awarded Yearling Feb14 awarded Nice Question Feb1 asked Delta Function Integration Jan26 comment Self-adjointness of $D=\frac{d^2}{dx^2}-1$ with boundary conditions $u'(0) = 0 = u'(a)$ on $[0,a]$. Also, sorry to everyone regarding the question editing--I left my computer open and a friend started messing with things. Jan26 comment Self-adjointness of $D=\frac{d^2}{dx^2}-1$ with boundary conditions $u'(0) = 0 = u'(a)$ on $[0,a]$. @JonasMeyer: I was able to figure that out. I can post what I came up with in a little bit. Jan25 revised Self-adjointness of $D=\frac{d^2}{dx^2}-1$ with boundary conditions $u'(0) = 0 = u'(a)$ on $[0,a]$. deleted 76 characters in body Jan25 revised Integral asymptotic expansion of $\int_{0}^{\infty} \frac{e^{-x \cosh t}}{\sqrt{\sinh t}}dt$ for $x \to \infty$ deleted 148 characters in body Jan25 revised Self-adjointness of $D=\frac{d^2}{dx^2}-1$ with boundary conditions $u'(0) = 0 = u'(a)$ on $[0,a]$. deleted 220 characters in body Jan24 asked Self-adjointness of $D=\frac{d^2}{dx^2}-1$ with boundary conditions $u'(0) = 0 = u'(a)$ on $[0,a]$. Jan24 asked Integral asymptotic expansion of $\int_{0}^{\infty} \frac{e^{-x \cosh t}}{\sqrt{\sinh t}}dt$ for $x \to \infty$ Jan10 accepted Annoying Green's Function Jan10 comment Annoying Green's Function oen: Thanks, I appreciate it! Jan10 comment Annoying Green's Function oen: I made a mistake when writing the question that I just realized. $f(x)$ is now corrected in the original post. I was able to get the Green's function you have, but applying it in the integral with the correct interval and everything was giving me fits. Could you walk me through this with the corrected $f(x)$ if you don't mind? Jan10 revised Annoying Green's Function added 1 characters in body Jan10 comment Annoying Green's Function The solution I listed is for the subregion $0 \le b \le a$! Jan9 asked Annoying Green's Function Jan9 comment Second-Order Differential Equation--Frobenius Method What happened to the $x^2$ in the denominator of the "y" term? Also, can you briefly explain how you got to the "approximated differential equation? Thanks! Jan8 comment Second-Order Differential Equation--Frobenius Method How is 0 not a singular point? And the ansatz is $y(x)=\sum_{n=0}^{\infty}a_n x^n.$