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 Oct25 awarded Yearling Jul2 awarded Curious May16 awarded Nice Question Nov30 accepted Prove $(1-\epsilon )\cdots(1-\epsilon ^{n-1})=n$ where $\epsilon = \exp(\frac{2\pi i}{n}), n\in \mathbb{N}, n \neq {0,1}$ Nov30 asked Prove $(1-\epsilon )\cdots(1-\epsilon ^{n-1})=n$ where $\epsilon = \exp(\frac{2\pi i}{n}), n\in \mathbb{N}, n \neq {0,1}$ Oct25 awarded Yearling Jun11 accepted Limit calculation using Riemann integral Jun9 awarded Teacher Jun9 comment Limit calculation using Riemann integral Integration is easy, everyone can do it on his own, I hope it is now correct :) Jun9 answered Limit calculation using Riemann integral Jun9 comment Limit calculation using Riemann integral aaa.... so the answer is just the sum of two integrals? Jun9 asked Limit calculation using Riemann integral May21 accepted Calculate the length of curve $f(x)=\arcsin(e^x)$, check solution, please. May21 comment Calculate the length of curve $f(x)=\arcsin(e^x)$, check solution, please. And the result will be in terms of summation, doesn't it? May21 comment Calculate the length of curve $f(x)=\arcsin(e^x)$, check solution, please. However the integral is still nasty, is this correct way to do it? May21 comment Calculate the length of curve $f(x)=\arcsin(e^x)$, check solution, please. $\frac{1}{\sqrt{1-x^2}}$... May21 asked Calculate the length of curve $f(x)=\arcsin(e^x)$, check solution, please. Apr25 comment Functions $f, g$ are given. We know that we can expand them into power series around $x_0=0$, they also satisfy: $f(\frac{1}{k})=g(\frac{1}{k})$ … ee... a contradiction of what? You mean such a function that the statement is not true? Apr25 asked Functions $f, g$ are given. We know that we can expand them into power series around $x_0=0$, they also satisfy: $f(\frac{1}{k})=g(\frac{1}{k})$ … Apr24 answered Power Series Proof w/ Binomial Coef.