22,007 reputation
42866
bio website ie.linkedin.com/in/aymanh
location Dublin, Ireland
age
visits member for 3 years, 7 months
seen 9 mins ago

Senior software engineer at Google. B.Sc. and M.Sc. in Computer Science, Software Engineering. Studying for a M.Sc. in Mathematics.


5h
comment Atiyah-Macdonald 2.3
Did you solve exercise 2.15 on page 27? Once you solve it, the problem here becomes an immediate application of the exercise and proposition 2.14.
9h
answered Homotopy classes of maps from the projective plane to $S^1 \times S^3$
1d
comment To prove the sum is convergent
This has been asked many times before. Use Cauchy-Schwarz.
2d
comment Prove that intersection of connected spaces is connceted.
@ᴊᴀsᴏɴ Look carefully. It is a union in the book.
Jul
21
comment How to evaluate $\sum_{n=1}^{38}\sin\left(\frac{n^8\pi}{38}\right)$
@Mercy Yeah, misread. Never mind. I'll delete my comment.
Jul
21
revised How to evaluate $\sum_{n=1}^{38}\sin\left(\frac{n^8\pi}{38}\right)$
edited title
Jul
21
comment Extending cellular maps between aspherical complexes
@Lano You're right. I missed this requirement. Edited in now. Thanks.
Jul
21
revised Extending cellular maps between aspherical complexes
added 233 characters in body
Jul
21
answered Extending cellular maps between aspherical complexes
Jul
19
revised How to find $\sum_{r=1}^{n} r^2\cos {(r\theta)}$
edited title
Jul
19
revised Prove the inequality $\sum_{i,j = 1}^n {{A_{i,j}}({x_i}^2 - {x_i}{x_j})} \ge 0 $
edited title
Jul
19
answered A homomorphism induces a continuous map from ${\rm Spec}(A') \to {\rm Spec}(A)$.
Jul
18
comment If an analytic function has an algebraic order $h$ at infinity then $\lim_{z\to\infty}z^{-h}f(z)$ is not zero nor is it infinity
Consider $f(z) = z^h$. Then $\lim_{z\to\infty} z^{-h}f(z) = 1$. Is this what you're asking?
Jul
18
comment Homology group of the join
@NajibIdrissi I agree. It depends on what the OP already knows. This fact is good to have in one's toolbox anyway.
Jul
18
comment Homology group of the join
Alternatively you can use the fact that the join is homotopy equivalent to the suspension of the smash product.
Jul
18
comment Proving that a function is analytic
@ChristianBlatter That's a good point. This requires similar steps as in my original answer, but it also gives an expression for $H'$.
Jul
18
revised Proving that a function is analytic
added 403 characters in body
Jul
18
revised Proving that a function is analytic
added 2 characters in body
Jul
18
answered Proving that a function is analytic
Jul
17
comment Theoretical computer science text for mathematician
@Bananarama Yes, both are books of Mathematics. Have a look at the previews available to see if you like the style.