Reputation
1,356
Next privilege 2,000 Rep.
Edit questions and answers
Badges
2 18
Newest
 Benefactor
Impact
~9k people reached

May
19
comment Approximating $e^{x}/(e^{x} - 1)$
It depends where you'd like to approximate it ;)
May
18
asked The asymptotic upper density of $\{xy \colon 1\le x\le y\le 2x\}$
May
6
revised Filtering a sum of reciprocal of integers
added 110 characters in body
May
6
accepted Only finitely many $a, b$ such that $2+3^n+5^{n^2}=2^a7^b$ for some $n$?
May
6
revised Filtering a sum of reciprocal of integers
added 14 characters in body; edited title
May
6
asked Filtering a sum of reciprocal of integers
May
2
comment Only finitely many $a, b$ such that $2+3^n+5^{n^2}=2^a7^b$ for some $n$?
If it is a solution for a fixed $n$, then it is exactly one: it is asked to prove that there exist only finitely many $n$ such that the dophantine equation has (a) solution..
May
2
answered Check the convergence of $a_{n+1}=\sqrt{a_n+\frac{4}{a_n}}$ where $a_1=4$
May
2
asked Only finitely many $a, b$ such that $2+3^n+5^{n^2}=2^a7^b$ for some $n$?
May
2
answered If $m, n$ be positive integers, prove that $\phi(mn)=\phi((m,n))\phi([m,n])$, where $(m,n)=$ gcd of $m, n$ and $[m, n]=$ lcm of $m, n$.
May
2
comment If $m, n$ be positive integers, prove that $\phi(mn)=\phi((m,n))\phi([m,n])$, where $(m,n)=$ gcd of $m, n$ and $[m, n]=$ lcm of $m, n$.
Oh I see now that (6,9) is not a counterexample for the new problem. Wait, I put it in a new answer
May
1
comment If $m, n$ be positive integers, prove that $\phi(mn)=\phi((m,n))\phi([m,n])$, where $(m,n)=$ gcd of $m, n$ and $[m, n]=$ lcm of $m, n$.
Indeed, he asks for $\varphi(m)\varphi(n)$, not $\varphi(mn)$ [recall that they are equal if and only if m and n are coprime, as expected..]
Apr
30
comment If $m, n$ be positive integers, prove that $\phi(mn)=\phi((m,n))\phi([m,n])$, where $(m,n)=$ gcd of $m, n$ and $[m, n]=$ lcm of $m, n$.
I have the fifth edition.. Can you check where is it exactly?
Apr
29
comment If $m, n$ be positive integers, prove that $\phi(mn)=\phi((m,n))\phi([m,n])$, where $(m,n)=$ gcd of $m, n$ and $[m, n]=$ lcm of $m, n$.
If you dont like the counterexample proof, and you want to claim the both statements above are true, then it should be that $\varphi(x)=x$ where $x=\text{gcd}(m,n)$. Do you agree that this is possible if and only if $x=1$?
Apr
29
comment If $m, n$ be positive integers, prove that $\phi(mn)=\phi((m,n))\phi([m,n])$, where $(m,n)=$ gcd of $m, n$ and $[m, n]=$ lcm of $m, n$.
I already proved you that your claim is wrong...
Apr
28
comment Is it possible to generate a solution for this? $p^2 + q^2 + r^2 = pqr $
What is the local magazine?
Apr
28
revised Is it possible to generate a solution for this? $p^2 + q^2 + r^2 = pqr $
added 179 characters in body
Apr
28
comment finiding a limit base on the limit of $e$
Right, fixed __
Apr
28
revised finiding a limit base on the limit of $e$
edited body
Apr
28
comment Is it possible to generate a solution for this? $p^2 + q^2 + r^2 = pqr $
Can you explain why these solutions (I didn't check they really work) are integers?