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seen Apr 22 '13 at 0:25

Apr
17
accepted convolution computation involving $e^{-x^2}$
Apr
16
accepted differential equation - solving a second-order ODE with variable coefficients
Apr
16
asked convolution computation involving $e^{-x^2}$
Apr
16
asked Analysis - Fourier Transforms - show that convolution of characteristic functions is continuous
Mar
30
awarded  Tumbleweed
Mar
23
accepted If $\mu$ is a complex measure, every set $E$ has $A \subset E$ so that $|\mu(A)| \ge \frac{1}{\pi}|\mu|(E).$
Mar
23
comment If $\mu$ is a complex measure, every set $E$ has $A \subset E$ so that $|\mu(A)| \ge \frac{1}{\pi}|\mu|(E).$
thank you very much
Mar
23
asked differential equation - solving a second-order ODE with variable coefficients
Mar
23
asked If $\mu$ is a complex measure, every set $E$ has $A \subset E$ so that $|\mu(A)| \ge \frac{1}{\pi}|\mu|(E).$
Mar
3
asked solve a system of linear differential equations with variable coefficients
Nov
20
awarded  Scholar
Nov
20
accepted inner product and adjoint operator
Nov
20
accepted self-adjoint operator and unitary orthogonal matrix
Nov
20
accepted Find an adjoint; inner product
Nov
20
accepted dimension of orthonormal set
Nov
19
asked self-adjoint operator and unitary orthogonal matrix
Nov
12
comment Find an adjoint; inner product
Thank you. I obtained this same result, as noted above, only I used constants m,n rather than a,b. But I am not sure if the adjoint can be expressed in terms of the linear function's coefficients. Note how alpha is originally defined; the definition does not depend on its particular coefficients, but rather p(0) and p(1).
Nov
12
asked Find an adjoint; inner product
Nov
11
asked dimension of orthonormal set
Nov
4
awarded  Student