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 Oct28 awarded Popular Question Oct27 awarded Curious Apr17 accepted convolution computation involving $e^{-x^2}$ Apr16 accepted differential equation - solving a second-order ODE with variable coefficients Apr16 asked convolution computation involving $e^{-x^2}$ Apr16 asked Analysis - Fourier Transforms - show that convolution of characteristic functions is continuous Mar30 awarded Tumbleweed Mar23 accepted If $\mu$ is a complex measure, every set $E$ has $A \subset E$ so that $|\mu(A)| \ge \frac{1}{\pi}|\mu|(E).$ Mar23 comment If $\mu$ is a complex measure, every set $E$ has $A \subset E$ so that $|\mu(A)| \ge \frac{1}{\pi}|\mu|(E).$ thank you very much Mar23 asked differential equation - solving a second-order ODE with variable coefficients Mar23 asked If $\mu$ is a complex measure, every set $E$ has $A \subset E$ so that $|\mu(A)| \ge \frac{1}{\pi}|\mu|(E).$ Mar3 asked solve a system of linear differential equations with variable coefficients Nov20 awarded Scholar Nov20 accepted inner product and adjoint operator Nov20 accepted self-adjoint operator and unitary orthogonal matrix Nov20 accepted Find an adjoint; inner product Nov20 accepted dimension of orthonormal set Nov19 asked self-adjoint operator and unitary orthogonal matrix Nov12 comment Find an adjoint; inner product Thank you. I obtained this same result, as noted above, only I used constants m,n rather than a,b. But I am not sure if the adjoint can be expressed in terms of the linear function's coefficients. Note how alpha is originally defined; the definition does not depend on its particular coefficients, but rather p(0) and p(1). Nov12 asked Find an adjoint; inner product