Lukas Arvidsson
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 Feb4 awarded Popular Question Jan15 accepted How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$ Jan15 comment How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$ Thank you! This is indeed correct! Jan15 comment How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$ You are right, this is not wrong, I was not understanding the question properly. Thank you! I have been pulling my hair for a while on this question now :) Jan15 asked How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$ Jan15 accepted How to best approach a problem of this kind (problem solving and simple linear equations) Jan15 comment How to best approach a problem of this kind (problem solving and simple linear equations) Thank you Joffan! This is indeed correct and it is maybe the best way to do it! Jan15 asked How to best approach a problem of this kind (problem solving and simple linear equations) Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you Christian! I will study your answer thoroughly! Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you for your clear explanation hunter! Much appreciated! Jan15 accepted Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you very much for your answer Marc! Great!! Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you again for your comment, I have changed the matrices to apply from the left instead. Jan15 revised Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. edited body Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. You are correct, I have changed that now. Thank you! Jan15 revised Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. deleted 9 characters in body Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you for your comments Peter! If you could please elaborate on what you mean a bit more (and maybe write that as an aswer) I would be very happy! Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you for your answer! If you have the time, could you please elaborate on where the reasoning in my question is incorrect in relation to your answer? Jan15 comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. Thank you, that is right! I have edited this now. Jan15 revised Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations. edited body