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Feb
4
awarded  Popular Question
Jan
15
accepted How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$
Jan
15
comment How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$
Thank you! This is indeed correct!
Jan
15
comment How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$
You are right, this is not wrong, I was not understanding the question properly. Thank you! I have been pulling my hair for a while on this question now :)
Jan
15
asked How to understand $Re(z) + Im(z) = 2$ & $Re(z) - Im(z) = 0$, $z \in \mathbb{C}$
Jan
15
accepted How to best approach a problem of this kind (problem solving and simple linear equations)
Jan
15
comment How to best approach a problem of this kind (problem solving and simple linear equations)
Thank you Joffan! This is indeed correct and it is maybe the best way to do it!
Jan
15
asked How to best approach a problem of this kind (problem solving and simple linear equations)
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you Christian! I will study your answer thoroughly!
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you for your clear explanation hunter! Much appreciated!
Jan
15
accepted Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you very much for your answer Marc! Great!!
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you again for your comment, I have changed the matrices to apply from the left instead.
Jan
15
revised Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
edited body
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
You are correct, I have changed that now. Thank you!
Jan
15
revised Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
deleted 9 characters in body
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you for your comments Peter! If you could please elaborate on what you mean a bit more (and maybe write that as an aswer) I would be very happy!
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you for your answer! If you have the time, could you please elaborate on where the reasoning in my question is incorrect in relation to your answer?
Jan
15
comment Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
Thank you, that is right! I have edited this now.
Jan
15
revised Intuitive understanding of the $BAB^{-1}$ formula for changing basis in linear transformations.
edited body