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Apr
25
asked truth table of equivalence relation
Mar
1
asked linear regression optimization
Feb
18
awarded  Promoter
Feb
18
awarded  Tumbleweed
Feb
11
asked transform from the replication equation to the Lotka-Volterra
Feb
3
accepted explanation of slope in a graph?
Feb
3
asked explanation of slope in a graph?
Jan
30
accepted what does the inverse membership symbol means?
Jan
29
asked what does the inverse membership symbol means?
Jan
22
accepted What is the difference between a polynomial regression and a generalized linear model?
Jan
22
awarded  Student
Jan
22
comment What is the difference between a polynomial regression and a generalized linear model?
@StefanHansen, it could be something like this client_pref = c0 + c1 * year + c2 * bimonthly. For the second case it would be bodyfat=age+breast+arms. I dont know why I cannot use abline in the first case. For what some people told me is because in the first case I will have a hyperplane, but in the second one not. In the second case I got three variables so why I cannot get an hyperplane also
Jan
22
comment What is the difference between a polynomial regression and a generalized linear model?
@StefanHansen, I have included two examples, maybe you can give me a hint with that
Jan
22
revised What is the difference between a polynomial regression and a generalized linear model?
added 313 characters in body
Jan
22
comment What is the difference between a polynomial regression and a generalized linear model?
exactly, but I saw a case in which there were no exponents. I think that it has to be that the predictor variables have no relationship within each other, but in the second case they have. For example first case could be about prediction of consumer interest yearly and each two months; while the second one could be about weight prediction for a person taking the measures of other parts of their body
Jan
22
asked What is the difference between a polynomial regression and a generalized linear model?
Jan
20
awarded  Scholar
Jan
20
awarded  Supporter
Jan
20
comment Prove - In $\frac{1}{{2}^{\lambda }}\leq \frac{1}{{\lambda }^{d}}$, there exists a large value of $\lambda$, so that the equation holds for any $d$.
thanks @marty cohen, I have been thinking in the first part of the solution that I mentioned, but I was missing the rest of it. It was very helpful your post
Jan
20
accepted Prove - In $\frac{1}{{2}^{\lambda }}\leq \frac{1}{{\lambda }^{d}}$, there exists a large value of $\lambda$, so that the equation holds for any $d$.