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| bio | website | |
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| location | ||
| age | ||
| visits | member for | 7 months |
| seen | May 14 at 4:22 | |
| stats | profile views | 17 |
Student at UC Berkeley studying Engineering, Mathematics, & Statistics.
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May 9 |
comment |
Need help understanding statement of Van Kampen's Theorem and using it to compute the fundamental group of Projective Plane Ah, I see. It's incorrect to say that by inclusion I get $a^2 = 1$ in $\pi_1(U)$; that equality is only true in $\pi_1({\bf RP^2})$ because in that case the loop $a^2$ can be homotoped to the trivial loop. Thanks for your response. |
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May 9 |
awarded | Scholar |
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May 9 |
accepted | Need help understanding statement of Van Kampen's Theorem and using it to compute the fundamental group of Projective Plane |
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May 9 |
asked | Need help understanding statement of Van Kampen's Theorem and using it to compute the fundamental group of Projective Plane |
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Nov 16 |
awarded | Enthusiast |
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Nov 11 |
revised |
Crofton's formula for regular curves added 15 characters in body |
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Nov 11 |
revised |
Crofton's formula for regular curves deleted 1 characters in body |
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Nov 11 |
answered | Crofton's formula for regular curves |
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Nov 6 |
awarded | Student |
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Nov 5 |
comment |
Minimal surfaces and gaussian and normal curvaturess This is not correct. $x_{12} \cdot n$ is not $0$. Result is still correct since $F=0$, however. |
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Nov 2 |
comment |
Prove that $X$ parametrizes a regular surface $M$ in $\mathbb{R}^3$ and determine for which values $p$ the curve $y$ is geodesic on $M$. You should not set $<X_t,y \prime\prime>$ and $<X_p,y \prime\prime>$ equal to $0$. A geodesic is defined by $<S,y \prime\prime>=0$ where $S$ is the intrinsic normal vector. In other words, if $T$ is the tangent for the curve $y$, and $n$ is the normal vector to the surface, then $S = n\times T$. You should probably figure out $T$. You already found $n$. Then just calculate $S$ and solve for $p$ in $<S,y \prime\prime>=0$ |
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Oct 25 |
comment |
curve evolution length formula Can you explain a bit why $\frac {d \gamma \prime}{dt}$ is equivalent to $\frac {dv}{ds}$? |
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Oct 25 |
comment |
curve evolution length formula You're correct about the physical aspect of velocity having direction, I forgot about that. Though it's interesting, in my text, the section on non-unit speed curves defines v to be $|d\beta/dt|$ anyway. And the second point you bring up is good, I wonder if there's been a mistake in writing the question. |
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Oct 25 |
answered | Prove that $f$ is uniformly continuous on the interval $(a,d)$ |
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Oct 25 |
comment |
curve evolution length formula Take the dot to just be multiplication, not dot product. The result is a scalar so I don't understand your parenthetical objection. |
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Oct 22 |
awarded | Supporter |
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Oct 22 |
comment |
Error in quadratic interpolation to $f(x)=1/x$? Sorry, I don't understand. From what I can see, your answer is the same as the book's. You are confused what the symbol e-1 means. The only thing I can think is that you are taking e to be the constant, as in 2.71828..., but occasionally the notation e-1 means "take this number and multiply by 10 to the power -1". Often calculators use this notation so they don't have to display a long string of $0$'s. Is this your confusion? |
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Oct 22 |
awarded | Editor |
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Oct 22 |
comment |
Error in quadratic interpolation to $f(x)=1/x$? It is. I edited my post with the work. |
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Oct 22 |
revised |
Error in quadratic interpolation to $f(x)=1/x$? Added some algebra to show they are the same. |
