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Jan
22
comment a question related to two competing patterns in coin tossing
@PEV: So if that's a fair coin, you're saying the probability is $1/32$. Of course, that's the probability that a random flip sequence of length 5 is equal to HTHTH but doesn't seem to answer whether HTHTH or HTHH is more likely to appear first.
Jan
22
comment a question related to two competing patterns in coin tossing
Sorry, but does this actually answer either of the part of the problem? I'm (not very familiar with Markov chains and am) confused about what the mean time tells you. (And I'm assuming $q = 1 - p$; is that right?)
Jan
22
comment a question related to two competing patterns in coin tossing
I'm also interested to know how to solve this problem; I've seen variations a few times on contests but never knew how to solve it.
Dec
11
awarded  Quorum
Nov
16
awarded  Enlightened
Nov
16
awarded  Nice Answer
Oct
1
awarded  Enlightened
Sep
16
comment Finding $\lim\limits_{n \to \infty} \sum\limits_{k=0}^n { n \choose k}^{-1}$
Why is the text on this so big?
Aug
19
awarded  Good Answer
Aug
3
comment Solve an equation with linear and exponential functions, $x=10^{x/10}$
Besides, that's not a complete answer. x ≈ 1.37129 works as well.
Jul
30
comment Which average to use? (RMS vs. AM vs. GM vs. HM)
Isaac: Thanks, fixed.
Jul
30
comment Which average to use? (RMS vs. AM vs. GM vs. HM)
Qiaochu Yuan: Can you elaborate a little more? I'm not sure you mean by rotational invariance. How are you rotating the values?
Jul
30
accepted Which average to use? (RMS vs. AM vs. GM vs. HM)
Jul
30
revised Which average to use? (RMS vs. AM vs. GM vs. HM)
edited body
Jul
30
comment Which average to use? (RMS vs. AM vs. GM vs. HM)
(Couldn't decide whether or not this is appropriate for this site; vote to close at will.)
Jul
30
asked Which average to use? (RMS vs. AM vs. GM vs. HM)
Jul
30
comment Proof that $n^3+2n$ is divisible by 3
Indeed. If you do enough problems like this, then at least tricks like this become second nature.
Jul
30
revised Proof that $n^3+2n$ is divisible by 3
edited body
Jul
30
comment Counting how many hands of cards use all four suits
This is a fantastic solution that I hadn't thought of. Thanks!
Jul
30
accepted Counting how many hands of cards use all four suits