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| bio | website | benalpert.com |
|---|---|---|
| location | United States | |
| age | 20 | |
| visits | member for | 2 years, 10 months |
| seen | 2 hours ago | |
| stats | profile views | 344 |
Khan Academy / Carnegie Mellon
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Apr 27 |
revised |
How to solve this recurrence relation? (convolution integral) edited tags |
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Apr 27 |
revised |
When is a recurrence relation linear edited tags |
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Apr 27 |
revised |
There is a table of the complexity of recursive algoritms? edited tags |
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Apr 26 |
comment |
Calculating the highest possible damage achievable using 6 items from a pool of ~25 Probably belongs on SO. |
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Apr 25 |
comment |
Inclusion-exclusion principle: Number of integer solutions to equations @DAK: Reread Gerry's last paragraph. For the intersection of $A_1$ and $A_2$, it's equivalent to solving $v_1+v_2+y_3+y_4=5$ with $v_1, v_2, y_3, y_4 \ge 0$. Just like the number of solutions to solve $y_1+y_2+y_3+y_4 = 12$ is $C(15,3)$, the number of solutions to that equation (and the size of the $\lvert A_1 \cap A_2 \rvert$ set) is $C(8,3)$. |
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Apr 25 |
comment |
Inclusion-exclusion principle: Number of integer solutions to equations I agree, I think it's $C(12 + 4 - 1, 3) = C(15,3)$. |
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Apr 16 |
awarded | Nice Question |
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Apr 13 |
comment |
Can (x'y' + xy) be simplified? @Brandon: You should probably write that as an answer. |
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Apr 13 |
comment |
Draw customized (calculus) graphs like these? Not sure whether to flag it, but I have enough rep to retag stuff so I got rid of the graph-theory tag. |
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Apr 13 |
revised |
Draw customized (calculus) graphs like these? edited tags |
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Apr 12 |
suggested | suggested edit on Probability of having at least 'k' marbles specific to each of 'm' bags filled by sampling with replacement |
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Mar 31 |
comment |
Interpreting “lying on the parabolas” Out of curiosity, how do you get Mathematica to make that? |
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Mar 27 |
revised |
On deriving the arclength of a hyperbola Just formatting. |
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Mar 27 |
suggested | suggested edit on On deriving the arclength of a hyperbola |
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Mar 20 |
comment |
Numbers satisfying $\binom{n}{k} = m!$ I just wrote a script and I don't believe there are any others up to 13! (except of course $\binom{n}{0}$ and $\binom{n}{1}$). |
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Mar 20 |
revised |
expected area of a triangle determined by randomly placed points fix formatting again |
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Mar 20 |
suggested | suggested edit on expected area of a triangle determined by randomly placed points |
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Mar 20 |
revised |
expected area of a triangle determined by randomly placed points fixed formatting |
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Mar 20 |
suggested | suggested edit on expected area of a triangle determined by randomly placed points |
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Mar 20 |
revised |
Non-Standard Deviation absolute value instead of diff() |
