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Oct
23
comment Hölder type of inequality?
This is what I was in the process of typing out, except I think the top line should be $F(W_t)-F(0)$?
Oct
23
comment Hölder type of inequality?
I am confused, do you mean $f''(z)$?
Oct
23
comment Calculate the MLE for a parameter 𝜆
why are people upvoting this question? the questioner made no effort what so ever.
Oct
23
comment Calculate the MLE for a parameter 𝜆
@sara.t do you even know what you asked?
Oct
23
comment Calculate the MLE for a parameter 𝜆
Nope, you do not mean cumulative density function. I am sure.
Oct
23
comment Losing less than $100 in a game of chance.
what do you mean you tried to take $P(X_n\geq -100)$.? Chebyshev, Markov inequality?
Oct
23
comment standardised random variable least square regression $X$ against $Y$, $Y$ against $X$
@calculus regression minimises the total squared distance between realisations of $X$ and $Y$ to and the regression line, which goes through the origin in this case. I could have posed the question as I have a bunch of points $x_i$ and $y_i$ such that they have mean 0 and variance 1, the question would have still made sense.
Oct
23
comment standardised random variable least square regression $X$ against $Y$, $Y$ against $X$
@NormalHuman that is a helpful comment.
Oct
7
comment minimum number of times to change tyres.
To be honest, I do not even know how to prove the above solution is optimal. I cannot find any better solution does not constitute a proof!
Oct
5
comment Holder continuity constant and dervative.
I also know my fn are monotonically decreasing. Somehow my set of conditions allows to prove something, but it is hard to write down all of them
Oct
5
comment Holder continuity constant and dervative.
no, i have proved it before, but i forgot how it was done now...
Oct
5
comment Holder continuity constant and dervative.
Yes, also i know the derivatives of fn are bounded. I know f has derivatives everywhere except at one point, where it still admits left and right derivative, but not sure if they agree. Also fn and f are all convex.
Oct
3
comment If $f$ is continuously differentiable in $[a,b]$, $f(a)=f(b)$, and $f'(a)=f'(b)$, then there exist $a<x_1<x_2<b$ such that $f'(x_1) = f'(x_2)$.
i dont understand the down votes, because the arguments seems fine to me.
Oct
3
comment Variation of Coupon Collector's Problem
However, I also have to factor in the fact that the boxes themselves also have a probability to dispense coupons. -- not concise, in my opinion.
Oct
3
comment Variation of Coupon Collector's Problem
All of the parameters in the geometric distributions are halved, hence mean doubles... I do not understand your explanation, but you probably understood it. You can view as getting a geometric (p) but rejected with probability 1/2. This halves the parameter.
Oct
3
comment Variation of Coupon Collector's Problem
surely, this is just the answer of the normal problem, doubled?
Sep
10
comment Profit Share Distribution > 100% Total?
Well, yeah, I agree with you. This is a bit stupid and misleading.
Sep
10
comment Profit Share Distribution > 100% Total?
I googled your first line of text. So, what they meant is that suppose, I make £100, you lose £20, then the total profit between us is £80, then I make 125% of the profit you make -25%. My profit ratio is my profit / my profit+your profit. Similarly for yours.
Sep
10
comment Profit Share Distribution > 100% Total?
Not that I do not believe you, what you wrote makes no sense.
Sep
10
comment Profit Share Distribution > 100% Total?
Cannot see the full article...