4,822 reputation
21651
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location United Kingdom
age 25
visits member for 2 years, 3 months
seen Jan 25 at 21:09

Oct
29
accepted Binomial/Poisson distribution question
Oct
27
reviewed Approve Find the second derivative of a double integral
Oct
27
comment Binomial/Poisson distribution question
(2) and (4) are the same is my feeling too, thank you. I would like to have another confirmation before accepting this.
Oct
27
comment Binomial/Poisson distribution question
@Henry i am sorry, i am asking about (ii). I do not understand how it is different to (iv), maybe it is not. I would like an independent confirmation. I was meant to say 1,3,4 are easy...
Oct
27
revised Binomial/Poisson distribution question
added 1 character in body
Oct
27
asked Binomial/Poisson distribution question
Oct
26
reviewed Reopen monic irreducible polynomial over K
Oct
26
reviewed Close Calculate limits with “e”:
Oct
26
reviewed Close Draw a set of values in complex plane
Oct
26
reviewed Close Draw a set of values
Oct
26
reviewed Close Newton's Method Convergence
Oct
26
reviewed Close Prove that $\sum_{i=1}^na_i\sum_{i=1}^na^{-1}_i\ge n^2$ and $\sum_{i=1}^na_i^2\ge\frac1n$
Oct
26
reviewed Close A question about diffrentiability and integrablity
Oct
26
reviewed Close How can I prove that $\sup(\bigcup_{i \in I} A_{i}) =\sup\{\sup \,A_{i} : i \in I \}$?
Oct
26
reviewed Close Find $\lim_{n \to \infty} (0,9999+\frac{1}{\sqrt{n}})^n$ and $\lim_{n \to \infty} (1,00001-\frac{1}{n})^n$
Oct
26
reviewed Close Limit of the reciprocal of the mean harmonic
Oct
24
comment Normal distribution tail probability inequality
nice and easy...
Oct
24
comment Normal distribution tail probability inequality
so your approach is valid for $t\geq \sqrt{\pi/2}$. i do not know how to do it, so maybe, you start by assuming otherwise.
Oct
24
reviewed No Action Needed Normal distribution tail probability inequality
Oct
24
reviewed Approve process of $(a,b)R(c,d)\implies a\cdot b(b+c)=bc\cdot (a+d)$ being transistive relation..