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Jan
13
revised Distribution random variable $W=\sum_{k=1}^{\infty}X_k/2^k$
Improved title formating
Jan
13
awarded  Organizer
Jan
13
suggested approved edit on Distribution random variable $W=\sum_{k=1}^{\infty}X_k/2^k$
Jan
13
revised Distribution random variable $W=\sum_{k=1}^{\infty}X_k/2^k$
Improved formating
Jan
13
suggested approved edit on Distribution random variable $W=\sum_{k=1}^{\infty}X_k/2^k$
Jan
13
comment For which values of $p$ is the Markov chain recurrent? ( sort of a RW with two steps forward and one back)
No problem. What kind of solution do you look for?
Jan
12
answered For which values of $p$ is the Markov chain recurrent? ( sort of a RW with two steps forward and one back)
Dec
22
comment Confusion in the defition of 'first passage time' (Markov Chains)
When the time is discrete, works for me to see the markov chain as a infinity vector such that the $n$th coordinate indicates which state the process was at time $n$. In this context, $T_i$ is the first coordinate (time) you see the state $i$ in this vector. Was I clear?
Dec
21
answered Convergence of Martingale: Exercise (Durrett 5.5.7)
Oct
14
awarded  Yearling
Jul
26
comment Expected maximum degree Erdős–Rényi graph
I believe you can do more than that. Once the degree of each vertex follows a binomial distribution of parameters $N-1$ and $p$, via Chernoff bounds you can assure that every vertex is close to his expected value. Then, the maximum degree will be close of $(N-1)p$ with high probability.
Jun
24
revised Is my answer correct? Expected number of coin flips to get 5 consecutive heads
added 55 characters in body
Jun
24
comment Is my answer correct? Expected number of coin flips to get 5 consecutive heads
Thanks! you too.
Jun
24
comment Is my answer correct? Expected number of coin flips to get 5 consecutive heads
Well, I see this kind of solution, usually, in problems involving Discrete Markov Chains. The Gambler's ruin, the first run of three sixes, the secretary problem are classical problems of the subject.
Jun
24
comment Is my answer correct? Expected number of coin flips to get 5 consecutive heads
No problem, it isn't my first language too. Well, now I get it. And it is correct.
Jun
24
answered Is my answer correct? Expected number of coin flips to get 5 consecutive heads
Jun
24
comment Is my answer correct? Expected number of coin flips to get 5 consecutive heads
I tried to understand the definition of your $X_i$ but I failed. Could you explain again? I didi't understand what you meant by "probability of the random variable $X_i$."
Jun
19
answered What is $\lim_{x\to 0} \sum_{n=2}^\infty \frac{\sqrt{x}\ln n}{1+n^2 x}$?
Jun
17
comment Convergence in distribution with finite mean
Unfortunately, it is wrong. If you simply take $X=Y$ in distribution you have that all the means are equals, thus you have convergence for the sequence they form.
Jun
12
answered Degree distribution of the line graph of an Erdös-Rényi random graph