125 reputation
3
bio website
location London, United Kingdom
age
visits member for 1 year, 11 months
seen Feb 3 at 15:03

printf("Hello, World!"); return 0;


Oct
9
accepted Conditional Probability using Venn Diagrams
Oct
9
comment Conditional Probability using Venn Diagrams
For part (iii), it is $P(A \cap B) \therefore \frac{1}{2} - \frac{1}{3} = \frac{1}{6}$. I think that's correct.
Oct
9
comment Conditional Probability using Venn Diagrams
I made a typo, it should be $\frac{1}{3}$
Oct
9
revised Conditional Probability using Venn Diagrams
edited body
Oct
9
comment Conditional Probability using Venn Diagrams
@Henry Thanks, I've got a hold of the syntax, thanks to your edit.
Oct
9
revised Conditional Probability using Venn Diagrams
added 6 characters in body
Oct
9
asked Conditional Probability using Venn Diagrams
Oct
15
awarded  Scholar
Oct
15
accepted Algebra book(s): Beginner through to advanced
Oct
14
comment Algebra book(s): Beginner through to advanced
That looks perfect.
Oct
14
awarded  Editor
Oct
14
awarded  Student
Oct
14
revised Algebra book(s): Beginner through to advanced
edited title
Oct
14
asked Algebra book(s): Beginner through to advanced