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 Feb 12 awarded Yearling Apr 27 awarded Popular Question Jan 25 awarded Nice Question Dec 16 awarded Caucus Jul 26 awarded Notable Question Jan 16 awarded Popular Question Apr 27 accepted Sum over cosines = dirac delta - how to get the coefficients? Apr 27 comment Sum over cosines = dirac delta - how to get the coefficients? I edited my question, I forget the boundaries, sorry. Apr 27 revised Sum over cosines = dirac delta - how to get the coefficients? boundaries Apr 27 comment Sum over cosines = dirac delta - how to get the coefficients? @Did This is from a physical problem. There's the restriction $0 \leq x \leq d$. Apr 27 asked Sum over cosines = dirac delta - how to get the coefficients? Nov 10 comment Maybe Things Can be Divided by Zero But I could start with f(x) = x that is defined everywhere and expand it by x/x to f(x) = x^2/x. This should not be defined at x = 0 suddenly? Isn't it so that a function is defined everyhwere when the numerator has a higher power than the denominator? Or the other way round: If I take the limit z -> 1 in the question, I think this would be allowed and leead to the result 2. Nov 10 awarded Editor Nov 10 comment What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part? Because of Latex I'm actually here. I was wondering if there's a special reason why Latex defaults \Re and \Im to the Fraktur versions. Nov 10 revised What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part? corrected Latex Nov 10 comment What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part? Thanks, corrected. Nov 10 asked What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part? Nov 2 awarded Scholar Nov 2 awarded Supporter Nov 2 comment Partial derivative: Why does substitution order matter? Thanks all of you. I chose this answer as the correct one in combination with Willies comment which solved my problem fully ("independent" was the keyword, I was not aware of this).