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12h
awarded  Notable Question
Jan
16
awarded  Popular Question
Apr
27
accepted Sum over cosines = dirac delta - how to get the coefficients?
Apr
27
comment Sum over cosines = dirac delta - how to get the coefficients?
I edited my question, I forget the boundaries, sorry.
Apr
27
revised Sum over cosines = dirac delta - how to get the coefficients?
boundaries
Apr
27
comment Sum over cosines = dirac delta - how to get the coefficients?
@Did This is from a physical problem. There's the restriction $0 \leq x \leq d$.
Apr
27
asked Sum over cosines = dirac delta - how to get the coefficients?
Nov
10
comment Maybe Things Can be Divided by Zero
But I could start with f(x) = x that is defined everywhere and expand it by x/x to f(x) = x^2/x. This should not be defined at x = 0 suddenly? Isn't it so that a function is defined everyhwere when the numerator has a higher power than the denominator? Or the other way round: If I take the limit z -> 1 in the question, I think this would be allowed and leead to the result 2.
Nov
10
awarded  Editor
Nov
10
comment What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part?
Because of Latex I'm actually here. I was wondering if there's a special reason why Latex defaults \Re and \Im to the Fraktur versions.
Nov
10
revised What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part?
corrected Latex
Nov
10
comment What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part?
Thanks, corrected.
Nov
10
asked What's more common? Re / Im or Fraktur-R / Fraktur-I for real / imaginary part?
Nov
2
awarded  Scholar
Nov
2
awarded  Supporter
Nov
2
comment Partial derivative: Why does substitution order matter?
Thanks all of you. I chose this answer as the correct one in combination with Willies comment which solved my problem fully ("independent" was the keyword, I was not aware of this).
Nov
2
accepted Partial derivative: Why does substitution order matter?
Nov
2
comment Partial derivative: Why does substitution order matter?
partial derivative of f(x, g(x), h(x)) by x treats g and h as constant, I thought? Or the other way round: Then why partial derive at all if I'm not allowed to treat something as constant?
Nov
2
comment Partial derivative: Why does substitution order matter?
But I thought the partial derivative does exactly this: take everything as constant but the variable that shows up directly itself.
Nov
2
asked Partial derivative: Why does substitution order matter?