Leo
Reputation
Top tag
Next privilege 15 Rep.
Flag posts
 Oct 18 awarded Student Oct 15 comment Proving if equations are products of XOR Oh, I see what I did wrong. I get it thanks! Oct 15 revised Proving if equations are products of XOR deleted 209 characters in body Oct 15 comment Proving if equations are products of XOR $$A⊕B⊕A.B= A+B$$ $$\begin{array}{c|c|c} A&B&A\oplus B&A\cdot B&(A\oplus B)\oplus A\cdot B&A+B\\ \hline 0&0&0&0&0\oplus 0=0&0\\ 0&1&1&0&1\oplus 0=1&0\\ 1&0&1&0&0\oplus 1=1&0\\ 1&1&0&1&1\oplus 1=0&1 \end{array}$$ Oct 15 comment Proving if equations are products of XOR Following what you demostrated is this what the table is suppose to look like?@Brian M. Scott Oct 15 comment Proving if equations are products of XOR Okay thanks Ben. Oct 15 accepted Proving if equations are products of XOR Oct 15 revised Proving if equations are products of XOR added 160 characters in body Oct 14 asked Proving if equations are products of XOR Oct 10 comment Boolean simplification Okay, I get it! Thanks copper.hat. Oct 10 comment Boolean simplification Thank you by the way. Oct 10 accepted Boolean simplification Oct 10 comment Boolean simplification Alright excuse my ignorance but what rule is that? Also after each step a variable was dropped. Why is that? i.e. D',C',A. Where do they go? Are they get canceled out? Oct 10 awarded Editor Oct 10 revised Boolean simplification added 69 characters in body Oct 10 asked Boolean simplification Oct 10 asked Boolean Function Oct 10 comment Boolean Simplification Thanks Brain for help. Oct 10 comment Boolean Simplification Alright that makes sense. My question is now do we always follow those same steps? i.e. de Morgans, distribute laws, absorption laws. Or does each equation go through a different approach, depending how it is presented? Oct 10 awarded Scholar