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visits member for 1 year, 11 months
seen 17 hours ago

Sep
9
awarded  Teacher
Sep
9
answered Vector word problem
May
14
awarded  Caucus
Apr
18
accepted Get polynom from polynom, roots of second one are multiplication of first one.
Apr
18
comment Get polynom from polynom, roots of second one are multiplication of first one.
The problem is, that c1,c2....cn are not known.
Apr
18
comment Get polynom from polynom, roots of second one are multiplication of first one.
I dont think so, can you be more descriptive please?
Apr
18
asked Get polynom from polynom, roots of second one are multiplication of first one.
Apr
10
accepted transform traveling salesman problem into subgraph isomorphism problem
Apr
7
comment transform traveling salesman problem into subgraph isomorphism problem
I can call the constant time subrutine that solve graph problem polynomial times, so its not a problem. Problem is, formulating the algorithm using this subroutine.
Apr
7
comment transform traveling salesman problem into subgraph isomorphism problem
I read, that if you could solve one NP-complete problem in constant time, you can solve them all, so I think that all NP-complete problems are transferable to each other.
Apr
7
asked transform traveling salesman problem into subgraph isomorphism problem
Apr
7
accepted Maximum number of elements, where no two are in relation
Apr
6
comment Maximum number of elements, where no two are in relation
its restrictive condition
Apr
6
asked Maximum number of elements, where no two are in relation
Mar
16
comment Get A⊕(B+1) from A⊕B
I solve this in relation to cryptography. In my example n<=8, so the cipher can be bruteforced easily. Thanks a lot!
Mar
16
accepted Get A⊕(B+1) from A⊕B
Mar
16
comment Get A⊕(B+1) from A⊕B
That was stupid comment, I see now.
Mar
16
comment Get A⊕(B+1) from A⊕B
Ahh, I see. Thanks! Are two different values the maximum I can get? Can I get three(or more) different values of D for one C?
Mar
16
comment Get A⊕(B+1) from A⊕B
It means XORing bit by bit, edited question
Mar
16
asked Get A⊕(B+1) from A⊕B