malin

545 reputation

bio	website	http://-
	location	Sweden
	age	24
visits	member for	7 months
	seen	2 days ago
stats	profile views	30

I'm currently writing my master thesis in geometric measure theory at the University of Gothenburg.

	545 reputation	bio	website	http://-	visits	member for	7 months
13 badges		location	Sweden		seen	2 days ago

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May 7	awarded	Caucus
May 4	revised	Least common multiple Fixed spelling in the title
May 4	suggested	suggested edit on Least common multiple
May 3	comment	Is $\frac{\lfloor{x}\rfloor+1}{2} \le \lfloor\frac{x}{2}\rfloor + 1$ Thanks :) Now fixed!
May 3	revised	Is $\frac{\lfloor{x}\rfloor+1}{2} \le \lfloor\frac{x}{2}\rfloor + 1$ Fixed a typo
May 3	answered	Is $\frac{\lfloor{x}\rfloor+1}{2} \le \lfloor\frac{x}{2}\rfloor + 1$
Apr 30	comment	Pascal's triangle and combinatorial proofs It's quite unclear what you mean by a combinatorical proof.. Everything which holds by showing Pascals triangle also holds if using known identities for binomial coefficients?
Apr 25	revised	Function in $[0, 1]$ continuous in $\{0\}\cup (\mathbb{R\backslash Q}\cap [0, 1])$ fixed some spelling and grammar
Apr 25	suggested	suggested edit on Function in $[0, 1]$ continuous in $\{0\}\cup (\mathbb{R\backslash Q}\cap [0, 1])$
Apr 23	revised	What is wrong with this function handle? fixed some LaTeX typography
Apr 23	suggested	suggested edit on What is wrong with this function handle?
Apr 23	answered	What is wrong with this function handle?
Apr 20	awarded	Nice Question
Feb 22	suggested	suggested edit on Problem on Product Measure
Feb 20	asked	Does it exist a function for which the derivative changes sign more than countably many times?
Feb 5	comment	How to find this limit? At least one reason for your reasoning being wrong is that you are not allowed to take the limits of the denominator and numerator separately.
Feb 5	suggested	suggested edit on How to find this limit?
Feb 5	suggested	suggested edit on How to find this limit?
Feb 3	comment	Where can I find the proofs of these measure theory Propositions? In these lecture notes: math.chalmers.se/Math/Grundutb/GU/MMA110/A11/MeasureTheory.pdf
Feb 2	comment	Does this integral expression makes sense? Ut is undefined as long as you don't set its value of zero to something. If we set $f(x) = \frac{1}{x}$ for all $x \not = 0$ and then set $f(0) = A$ for some real number $A$, the integral $\int_{-1}^1 f(x) dx$ makes perfect sense.