1,476 reputation
21749
bio website
location Valdosta, ga
age 22
visits member for 2 years, 3 months
seen Jan 15 at 19:58

I am just a man who has an insatiable desire for knowledge.

"For the rest, brethren, whatever is true, whatever is worthy of reverence and is honorable and seemly, whatever is just, whatever is pure, whatever is lovely and lovable, whatever is kind and winsome and gracious, if there is any virtue and excellence, if there is anything worthy of praise, think on and weigh and take account of these things [fix your minds on them]."~ Philippians 4:8


Mar
1
comment Proving Complement Laws
Hmm, how interesting. I wonder what there apprehension was of toward using it.
Mar
1
comment Proving Complement Laws
Well, I am not familiar with intuitionistic logic, but I'll presume that being referred to as an intuitionist is a complement!
Mar
1
accepted Negative Binomial Question Without Exact Values
Mar
1
accepted Vector Function Magnitude
Mar
1
accepted Exposition On An Integral Of An Absolute Value Function
Mar
1
accepted Dot Product Of Vector Functions
Mar
1
accepted Representing A Plane Curve By A Vector Valued Function
Mar
1
asked Interpreting The Integral Of A Vector-Valued Function
Feb
28
accepted Proving Complement Laws
Feb
28
comment Proving Complement Laws
Thank you very much!
Feb
28
comment Proving Complement Laws
This is true because A and not A always partition the universe? I could have proved this in one step, right?
Feb
28
asked Proving Complement Laws
Feb
27
comment Definition of the complement of a set
@AndréNicolas How do you write "not an element" in latex, I couldn't figure it out.
Feb
27
accepted Definition of the complement of a set
Feb
27
comment Definition of the complement of a set
Yes. I do believe so. Thank you!
Feb
27
comment Definition of the complement of a set
Okay, I understand. One more question, in my book, the mathematical definition is given by $\bar{A} = \{x \in U | x \neg \in A \}$. Could I rewrite it as $\bar{A} = \{x| x \in U \wedge x \neg \in A \}$ Because it would most helpful to write it in that way for a proof I am working on.
Feb
27
asked Definition of the complement of a set
Feb
27
accepted Discrete Math Proof With Power-sets
Feb
27
comment Discrete Math Proof With Power-sets
Oh, so by taking the contrapositive, we would end up having to do a proof by contradiction?
Feb
27
comment Discrete Math Proof With Power-sets
Oh, yes. Those are some excellent suggestions. Thank you, amWhy!