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seen Dec 16 at 8:42

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comment Striking applications of integration by parts
@JakobH Note that the integration variable $t$ has a minus sign, $f(x-t)$.
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revised Action of $G/H$ on $H_n(H;M)$
Add concrete calculation with diagrams
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awarded  Explainer
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accepted Action of $G/H$ on $H_n(H;M)$
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comment Action of $G/H$ on $H_n(H;M)$
Many thanks for your answer! (I'll make a small edit and add the concrete calculation later.) Brown's book was not available in my university's library. A book by Lang mentioned that the action on the zeroth homology uniquely determines the action on higher homology groups via the long exact sequence / uniqueness of group homology, but a concrete calculation using this method seemed very daunting to me.
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reviewed Approve Evaluate the limit as $x$ approaches $3$ : $\displaystyle\frac{x^3 -6x+2}{x^2+2x-3}$
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comment Action of $G/H$ on $H_n(H;M)$
@tj_ Apparently, I'm missing the definition of the action. Could you elaborate it into a short answer? That would be much appreciated.
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comment Action of $G/H$ on $H_n(H;M)$
@tj_ Both are possible, the definition of homology is symmetric with respect to which module you resolve.
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comment Action of $G/H$ on $H_n(H;M)$
Oh! But wouldn't this mean that the Hochschild-Serre spectral sequence has only limited utility? Right now, it seems to me that in order to calculate the G/H action, I have to look at the bar resolution of $M$ as a $\mathbb{Z}[G]$-module, which I wanted to avoid doing in the first place by decomposing $G$ into $H$ and $G/H$. (Of course, I need some information about how $H$ sits inside $G$.) I was hoping for some "functorial" way of defining the action on $H_n(H;M)$.
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revised Action of $G/H$ on $H_n(H;M)$
Fixed resolution
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asked Action of $G/H$ on $H_n(H;M)$
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accepted Compact operators: why is the image of the unit ball only assumed to be relatively compact?