80 reputation
7
bio website contraflo.ws
location Sydney, Australia
age 24
visits member for 2 years
seen Mar 26 at 6:10

I am currently studying both Physics and Mathematics at the University of Sydney. My main interest areas are Differential Geometry and Particle Physics.


Jul
14
accepted Defining the coboundary map $\delta_*$ on the Sheaf Cech Cohomology groups
Jul
13
awarded  Teacher
Jul
12
answered Defining the coboundary map $\delta_*$ on the Sheaf Cech Cohomology groups
Jul
12
revised Defining the coboundary map $\delta_*$ on the Sheaf Cech Cohomology groups
More clarity
Jul
12
asked Defining the coboundary map $\delta_*$ on the Sheaf Cech Cohomology groups
May
20
accepted Show that $[l_1 \cdot l_2 \cdot l_3 ] = [l_1 + l_2 + l_3] \in H_1(X)$ The first Homology group of X
May
19
revised Show that $[l_1 \cdot l_2 \cdot l_3 ] = [l_1 + l_2 + l_3] \in H_1(X)$ The first Homology group of X
further part of the question
May
19
comment Show that $[l_1 \cdot l_2 \cdot l_3 ] = [l_1 + l_2 + l_3] \in H_1(X)$ The first Homology group of X
the $\cdot$ represents the usual path concatenation, whilst the addition $+$. I was hoping it was a conventional thing, as I guess that's where my confusion was coming from. I shall add additional parts of the question which may shed more light on the problem.
May
19
asked Show that $[l_1 \cdot l_2 \cdot l_3 ] = [l_1 + l_2 + l_3] \in H_1(X)$ The first Homology group of X
Nov
10
awarded  Tumbleweed
Nov
3
revised Find K and $\rho$ such that $|f_s| \leq K \rho^{-s}$ , with $f(z) = f_0 + f_1 z + \dots + f_s z^{s} + \dots$
added clarity
Nov
3
asked Find K and $\rho$ such that $|f_s| \leq K \rho^{-s}$ , with $f(z) = f_0 + f_1 z + \dots + f_s z^{s} + \dots$
Oct
13
awarded  Supporter
Oct
3
comment Proving $\frac{e^{z^2}}{\sqrt{\pi}}\int_{-\infty}^{z}e^{-t^2}dt$ is bounded for $\Re(z) \leq 0$
You need a reputation of at least 15 and I'm afraid I'm new here and only have 8. I've tried already.
Oct
3
awarded  Autobiographer
Oct
3
comment Proving $\frac{e^{z^2}}{\sqrt{\pi}}\int_{-\infty}^{z}e^{-t^2}dt$ is bounded for $\Re(z) \leq 0$
I was just wanting clarification on the statement of the theorem. The limit calculation is fine.
Oct
3
comment Proving $\frac{e^{z^2}}{\sqrt{\pi}}\int_{-\infty}^{z}e^{-t^2}dt$ is bounded for $\Re(z) \leq 0$
Thank you Giovanni, are you able to clarify what L'Hôpital's rule implies?
Oct
3
awarded  Scholar
Oct
3
accepted Proving $\frac{e^{z^2}}{\sqrt{\pi}}\int_{-\infty}^{z}e^{-t^2}dt$ is bounded for $\Re(z) \leq 0$
Oct
2
revised Proving $\frac{e^{z^2}}{\sqrt{\pi}}\int_{-\infty}^{z}e^{-t^2}dt$ is bounded for $\Re(z) \leq 0$
improving formatting