1,452 reputation
318
bio website kmlinux.fjfi.cvut.cz/…
location Prague, Czech Republic
age 27
visits member for 2 years, 2 months
seen 15 hours ago

Math PhD student at Czech Technical University in Prague and at LIAFA in Paris. At the same time, I'm a typesetter (and partly the copy editor) of one scientific journal (done in LaTeX, of course).

Code licence details applicable on my posts on TeX.SX.

My favourite queries on SE's Data Explorer


Feb
12
comment MENSA IQ Test and rules of maths
Well, you have to remember that MENSA is just a stupid company like any other company in the world, and that IQ is defined as the ability to pass IQ tests. The correllation of IQ with intelligence is unknown.
Feb
11
comment Is $7$ the only prime followed by a cube?
@Lost1 Congratulations, you've just observed that voting system of SE is screwed globally. (Still, it seems to quite well achieve to find local maxima).
Feb
6
comment Is any norm induced by some inner product?
@TobiasKildetoft Sorry, I was a bit too short-headed.
Feb
6
answered Is any norm induced by some inner product?
Jan
15
comment How to correctly do a division using a slash?
Well, the typical convention is that $a/bc=a/(bc)$ and $a/b\cdot c=(a/b)c$. But I would rely on it.
Jan
13
revised $X$ and $1 - X$ are identically distributed
Seperated two math blocks by some text to incread readability.
Jan
13
suggested approved edit on $X$ and $1 - X$ are identically distributed
Jan
13
awarded  Cleanup
Jan
13
revised Solve $12x\equiv9\pmod{15}$
rolled back to a previous revision
Jan
13
comment Integration $1/x$ - complex number
@HenningMakholm That's ridiculous, but you are probably right.
Jan
13
comment Solve $12x\equiv9\pmod{15}$
Lol, this looks like we have the very same idea :)
Jan
13
answered Solve $12x\equiv9\pmod{15}$
Jan
13
comment Integration $1/x$ - complex number
Since when the indefinite integral of a real function is a complex function, please?
Jan
13
answered Integration $1/x$ - complex number
Jan
13
comment Integration $1/x$ - complex number
No, it is not zero. Give me any extended real number, and using the definition I can "prove" that the value is this number. (Not that I'm willing to spend time on it. For an idea how to proceed, see Riemann series theorem.)
Jan
13
comment How is this not a metric?
I answered that one. It is not, with the counter-example I give.
Jan
13
comment How is this not a metric?
Oh, you answered yourself. Now it seems to me the question makes a little if any sense ;)
Jan
13
answered How is this not a metric?
Jan
13
comment Check if polynomial is minimal over $\mathbb{Q}$
Hi! Isn't more common notation for field adjoint $\mathbb{Q}(\sqrt2,\sqrt3)$? And btw, you mess up two things clearly. Your polynomial is the minimal polynomial of $\sqrt2+\sqrt3$ over $\mathbb Q$ -- do you search for a minimal polynomial over the other field?
Dec
21
comment 'mod' or 'remainder' symbol valid in maths?
Needed to add, if you wish to use a\%b in LaTeX to denote the remainder, you should write a \mathbin{\%} b or better define it by \renewcommand*{\bmod}{\mathbin{\%}} and then it's a \bmod b.