# tohecz

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bio website kmlinux.fjfi.cvut.cz/… location Prague, Czech Republic age 27 member for 2 years, 2 months seen 15 hours ago profile views 133

Math PhD student at Czech Technical University in Prague and at LIAFA in Paris. At the same time, I'm a typesetter (and partly the copy editor) of one scientific journal (done in LaTeX, of course).

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 Feb12 comment MENSA IQ Test and rules of maths Well, you have to remember that MENSA is just a stupid company like any other company in the world, and that IQ is defined as the ability to pass IQ tests. The correllation of IQ with intelligence is unknown. Feb11 comment Is $7$ the only prime followed by a cube? @Lost1 Congratulations, you've just observed that voting system of SE is screwed globally. (Still, it seems to quite well achieve to find local maxima). Feb6 comment Is any norm induced by some inner product? @TobiasKildetoft Sorry, I was a bit too short-headed. Feb6 answered Is any norm induced by some inner product? Jan15 comment How to correctly do a division using a slash? Well, the typical convention is that $a/bc=a/(bc)$ and $a/b\cdot c=(a/b)c$. But I would rely on it. Jan13 revised $X$ and $1 - X$ are identically distributed Seperated two math blocks by some text to incread readability. Jan13 suggested approved edit on $X$ and $1 - X$ are identically distributed Jan13 awarded Cleanup Jan13 revised Solve $12x\equiv9\pmod{15}$ rolled back to a previous revision Jan13 comment Integration $1/x$ - complex number @HenningMakholm That's ridiculous, but you are probably right. Jan13 comment Solve $12x\equiv9\pmod{15}$ Lol, this looks like we have the very same idea :) Jan13 answered Solve $12x\equiv9\pmod{15}$ Jan13 comment Integration $1/x$ - complex number Since when the indefinite integral of a real function is a complex function, please? Jan13 answered Integration $1/x$ - complex number Jan13 comment Integration $1/x$ - complex number No, it is not zero. Give me any extended real number, and using the definition I can "prove" that the value is this number. (Not that I'm willing to spend time on it. For an idea how to proceed, see Riemann series theorem.) Jan13 comment How is this not a metric? I answered that one. It is not, with the counter-example I give. Jan13 comment How is this not a metric? Oh, you answered yourself. Now it seems to me the question makes a little if any sense ;) Jan13 answered How is this not a metric? Jan13 comment Check if polynomial is minimal over $\mathbb{Q}$ Hi! Isn't more common notation for field adjoint $\mathbb{Q}(\sqrt2,\sqrt3)$? And btw, you mess up two things clearly. Your polynomial is the minimal polynomial of $\sqrt2+\sqrt3$ over $\mathbb Q$ -- do you search for a minimal polynomial over the other field? Dec21 comment 'mod' or 'remainder' symbol valid in maths? Needed to add, if you wish to use a\%b in LaTeX to denote the remainder, you should write a \mathbin{\%} b or better define it by \renewcommand*{\bmod}{\mathbin{\%}} and then it's a \bmod b.