1,365 reputation
214
bio website kmlinux.fjfi.cvut.cz/…
location Prague, Czech Republic
age 26
visits member for 1 year, 6 months
seen yesterday

Math PhD student at Czech Technical University in Prague and at LIAFA in Paris.

Code licence details applicable on my posts on TeX.SX.


Jan
13
answered Integration $1/x$ - complex number
Jan
13
comment Integration $1/x$ - complex number
No, it is not zero. Give me any extended real number, and using the definition I can "prove" that the value is this number. (Not that I'm willing to spend time on it. For an idea how to proceed, see Riemann series theorem.)
Jan
13
comment How is this not a metric?
I answered that one. It is not, with the counter-example I give.
Jan
13
comment How is this not a metric?
Oh, you answered yourself. Now it seems to me the question makes a little if any sense ;)
Jan
13
answered How is this not a metric?
Jan
13
comment Check if polynomial is minimal over $\mathbb{Q}$
Hi! Isn't more common notation for field adjoint $\mathbb{Q}(\sqrt2,\sqrt3)$? And btw, you mess up two things clearly. Your polynomial is the minimal polynomial of $\sqrt2+\sqrt3$ over $\mathbb Q$ -- do you search for a minimal polynomial over the other field?
Dec
21
comment 'mod' or 'remainder' symbol valid in maths?
Needed to add, if you wish to use a\%b in LaTeX to denote the remainder, you should write a \mathbin{\%} b or better define it by \renewcommand*{\bmod}{\mathbin{\%}} and then it's a \bmod b.
Dec
14
comment How to display matrices and other mathematical formulae
Please, no questions on TeX.SX concerning MathJaX if they have nothing to do with LaTeX itself. Of course, if the question applied both to MathJaX and LaTeX, it's fine.
Dec
14
comment Typesetting imaginary unit and bessel functions
As pointed before, the question seems off-topic here, it's not about LaTeX, rather about maths typesetting guidelines. AFAIK, this is on-topic on Math.SE.
Dec
10
revised $1/i=i$. I must be wrong but why?
added 92 characters in body
Dec
10
revised $1/i=i$. I must be wrong but why?
added 192 characters in body
Dec
10
comment $1/i=i$. I must be wrong but why?
+1 for $\pm\sqrt{a}$, -1 for the reasoning at the beginning. The wrong are all but the 2nd equality.
Dec
10
answered $1/i=i$. I must be wrong but why?
Nov
23
comment on two decompositions of a finite group $G$
+1 very nice, it just shows that people should be carefull about what they claim! However, it IMHO means that the OP likely wanted $AB=AC$ instead of $A\times B\cong A\times C$, which is what the other answer proves, and where your counterexample fails.
Nov
22
revised Cool simple solution to: $-A^2$ is not the identity matrix
markup corrected
Nov
22
suggested suggested edit on Cool simple solution to: $-A^2$ is not the identity matrix
Nov
22
answered Cool simple solution to: $-A^2$ is not the identity matrix
Nov
22
awarded  Civic Duty
Nov
22
comment Notation: Why do we learn to write the higher powers in an equation first?
@AsafKaragila I don't call that a series. That is a set of functions (most of which are not possible to express as series)
Nov
22
comment Notation: Why do we learn to write the higher powers in an equation first?
@AsafKaragila The convention for series is opposite because you can't write them in the same direction as polynomials.