10,917 reputation
2541
bio website math.rochester.edu/people/…
location Rochester, NY
age 25
visits member for 1 year, 6 months
seen 1 hour ago

I'm a graduate student at the U of R in Rochester, NY. I enjoy recreational mathematics including problem solving and most things topology.


Mar
8
answered prove $g(x)$ is continuous at $x=0$ and $f(x)$ isn't
Mar
7
comment Show the usual metric on $C([0,1])$ does not give rise to a complete metric space.
I'm not understanding your example. At first, it seems like $n$ is a positive integer, so you are looking at constant functions $1/n$. After that, you are taking $0<n<1$... It would be nice if you explained a little better what you are trying to do here.
Mar
6
answered Series of supremums
Feb
27
comment Pointwise Convergence in $L^1$ norm
Thanks, Davide! I had not thought about the Arzela-Ascoli theorem; you have proven something much better than I hoped! Thank you again :)
Feb
27
comment Pointwise Convergence in $L^1$ norm
Thank you for the clear response! I approached the problem in the wrong way; your technique is much better :)
Feb
27
accepted Pointwise Convergence in $L^1$ norm
Feb
27
asked Pointwise Convergence in $L^1$ norm
Feb
26
revised Calculate the series: $\sum^\infty_{n=1}\frac{(-1)^n}{n^2}$ using dirichlet's theorem
moved the -1/2 so the multiplication was more clear
Feb
20
comment Convex Functions are Continuous
@127.0.9.6: If you would like to type that up as an answer, I will accept it. Thank you :)
Feb
20
comment Convex Functions are Continuous
@JohnMoeller: I see that the top-voted answer claims that convex functions need not be continuous on general topological vector spaces; are normed vector spaces not restrictive enough? Thanks for the reference; I searched the site but was unable to find anything.
Feb
20
comment Convex Functions are Continuous
@littleO: We are given a function $F:\Bbb R\to(-\infty,\infty]$ with $F$ convex l.s.c. and $F(0)=0$. Our task is to prove $\varphi(x)=F(\Vert x\Vert)$ is convex l.s.c.
Feb
20
asked Convex Functions are Continuous
Feb
19
reviewed Reject suggested edit on Need help with a math proof
Feb
18
comment Prove that odd perfect square is congruent to $1$ modulo $8$
@Student: It is obvious. Clearly, precisely one of $k$ or $k+1$ is even, i.e., $2\mid k(k+1)$, in which case, $8\mid 4k(k+1)$. Amr explains this in his post as well.
Feb
17
answered Limit comparison Test with a suitable $b_k$
Feb
4
comment Complex exponential inequality .How to solve it?
@AntonioVargas: Thank you for bringing it to my attention!
Feb
4
comment Complex exponential inequality .How to solve it?
This is a spectacular answer! If it were possible, I'd upvote 10 times!
Jan
29
reviewed Approve suggested edit on Counterexample to a weak “definition” of group
Jan
22
comment How to improve my grades.
Probably one of the more common mistakes people make is that reproducing a proof for a theorem and being able to understand the proof well enough to apply to problems are not the same thing. My suggestion to you: do as many unseen exercises as you can. (Make sure they are at an appropriate level; as an undergraduate, doing graduate-level work might not suit you, but advanced undergraduate might be perfect.) Work on them for several hours before asking for help, but don't just stare at the problem. Look in books for possible theorems that might help you. Best of luck to you!
Jan
22
comment Finding $ \lim_{x \to 0^+} (\frac{\arctan (x)}{x})^{\frac{1}{x^2}} $ without power series.
The last identity should have an $h$ inside the parentheses, not $\frac{1}{h}$.