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| bio | website | www-ian.math.uni-magdeburg.de/… |
|---|---|---|
| location | Magdeburg, Germany | |
| age | 30 | |
| visits | member for | 2 years, 5 months |
| seen | May 15 at 10:53 | |
| stats | profile views | 478 |
I am an Australian mathematician.
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Jun 1 |
answered | Can I use Ravi Vakil's way of learning for elementary subjects? |
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May 31 |
comment |
Coordinate-free techniques in Lagrangian mechanics @Jor I take your point, but would like to also point out that if Akater is indeed still learning English and used the word inadvertently, then it is much better to become aware of standard (and dare I say it, correct) usage. I have yet to hear "somewhy" spoken. |
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May 31 |
comment |
Coordinate-free techniques in Lagrangian mechanics @Joriki, Akater: It's not really a word. The expression you are looking for is "for some reason". |
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May 30 |
comment |
How to prove that the Cantor ternary function is not weakly differentiable? The last part of the argument doesn't seem correct. The function $f(x) = 1/2$ for $x\in[0,1/2)$ and $f(x) = 2x-1/2$ seems to be a counterexample to the last claim. |
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May 30 |
comment |
Does there exists a absolute measure for growth-rate of a function? This question is ill-posed: what is your idea of absolute growth? |
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May 26 |
comment |
Constructive proof of boundedness of continuous functions Is this supposed to be a proof? |
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May 26 |
revised |
Is compactness a stronger form of continuity? correction |
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May 26 |
suggested | suggested edit on Is compactness a stronger form of continuity? |
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May 26 |
accepted | An elementary integral inequality |
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May 24 |
comment |
An elementary integral inequality Right. That's one point. (Well, actually two points.) The other is that we may be interested in an inequality which holds only on a fixed interval. Your idea still works, in a way, since then we can continue to perform a "limiting" argument through scaling. Then it will depend on the scaling of $A$ and $\alpha$. This is kind of what I was getting at. |
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May 23 |
comment |
An elementary integral inequality Yes I am vaguely aware of the families of reverse H\"older-type inequalities. I thought they might be overkill here, but you could very well be on to something---the extremals are well-studied and should yield something about best constants. |
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May 23 |
comment |
An elementary integral inequality Interesting. I wonder about the class $\alpha\in H^2$ say with $\int |\alpha''|^2 > 1$. |
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May 23 |
comment |
An elementary integral inequality The inequality actually is true (trivially, but still) for $a \ge b$. I like your little discussion, but have to disagree about the last few inequalities being "sharp". The sense I have in mind is that for certain classes of $\alpha$ the constant $a^p$ on the left hand side can be replaced by a larger constant. Your reasoning about the "best possible $f$" uses the original naive proof, so it won't detect any finer information about $\alpha$. Thanks for the answer! |
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May 23 |
comment |
An elementary integral inequality I guess I should have added calculus of variations to the tag list. |
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May 23 |
comment |
An elementary integral inequality @Martin Exactly! |
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May 23 |
comment |
An elementary integral inequality @Martin Ping! (extra chars) |
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May 23 |
comment |
An elementary integral inequality @Gerry, @Martin Yes... the proof is not really in question :). That's kind of what I was hinting at above. I'm more interested in 'sharpness' under various assumptions on $\alpha$. |
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May 23 |
asked | An elementary integral inequality |
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May 19 |
awarded | Vox Populi |
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May 19 |
awarded | Suffrage |
