345 reputation
110
bio website
location
age 23
visits member for 1 year, 10 months
seen Mar 26 at 21:31

Just a college student studying computer science. I'd like to learn some programming in my spare time as well so that's why I'm here!


Jul
2
awarded  Curious
Mar
26
revised Prove $F_{n+2} \ge x^n$ by induction where $x = (1 + \sqrt{5})/2$
Added note
Mar
26
revised Prove $F_{n+2} \ge x^n$ by induction where $x = (1 + \sqrt{5})/2$
added 4 characters in body
Mar
26
asked Prove $F_{n+2} \ge x^n$ by induction where $x = (1 + \sqrt{5})/2$
Mar
4
accepted Solution to this Geometric Series
Mar
4
asked Solution to this Geometric Series
Dec
1
awarded  Popular Question
Nov
6
awarded  Nice Question
Oct
1
awarded  Yearling
Apr
4
comment Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
I understand that. Thanks.
Apr
4
asked prove that the greatest number of regions that $n \geq 1$ circles can divide the plane is $n^2-n+2$
Apr
4
comment Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
So would the $2-1/k$ on the LHS basically come from $1/k^2<=2-1/k+1/(k+1)^2<=2-1/(k+1)$ omitting the first part of the inequality?
Apr
4
accepted Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
Apr
4
comment Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
Could you explain the first step for me. I'm confused about where the 2 came from on the LHS.
Apr
4
asked Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
Apr
4
accepted Show that the sum of 2n + 1 consecutive integers is divisible by 2n + 1.
Apr
4
comment Show that the sum of 2n + 1 consecutive integers is divisible by 2n + 1.
In regards to the first result, that would come from something like $b|a$ is the same as $a=bq$, correct?
Apr
4
asked Show that the sum of 2n + 1 consecutive integers is divisible by 2n + 1.
Apr
4
accepted Prove $(n^5-n)$ is divisible by 5 by induction.
Apr
4
comment Prove $(n^5-n)$ is divisible by 5 by induction.
That last sentence clears up my confusion. Thanks.