blutuu

328 reputation

bio	website
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	age	22
visits	member for	7 months
	seen	Apr 15 at 5:11
stats	profile views	75

Just a college student studying computer science. I'd like to learn some programming in my spare time as well so that's why I'm here!

	328 reputation	bio	website		visits	member for	7 months
7 badges		location			seen	Apr 15 at 5:11

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Apr 4	comment	Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$ I understand that. Thanks.
Apr 4	asked	prove that the greatest number of regions that $n \geq 1$ circles can divide the plane is $n^2-n+2$
Apr 4	comment	Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$ So would the $2-1/k$ on the LHS basically come from $1/k^2<=2-1/k+1/(k+1)^2<=2-1/(k+1)$ omitting the first part of the inequality?
Apr 4	accepted	Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
Apr 4	comment	Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$ Could you explain the first step for me. I'm confused about where the 2 came from on the LHS.
Apr 4	asked	Prove that for every positive integer $n$, $1/1^2+1/2^2+1/3^2+\cdots+1/n^2\le2-1/n$
Apr 4	accepted	Show that the sum of 2n + 1 consecutive integers is divisible by 2n + 1.
Apr 4	comment	Show that the sum of 2n + 1 consecutive integers is divisible by 2n + 1. In regards to the first result, that would come from something like $b\|a$ is the same as $a=bq$, correct?
Apr 4	asked	Show that the sum of 2n + 1 consecutive integers is divisible by 2n + 1.
Apr 4	accepted	Prove $(n^5-n)$ is divisible by 5 by induction.
Apr 4	comment	Prove $(n^5-n)$ is divisible by 5 by induction. That last sentence clears up my confusion. Thanks.
Apr 4	comment	Prove $(n^5-n)$ is divisible by 5 by induction. I understand the base case where it states $k^5 - k = 5n$, which holds true. Expanding $(k+1)^5$ shows that it also is a multiple of 5 which is visible by factoring ($k^5 - 5)--a multiple of 5. Am I reading that correctly?
Apr 4	comment	Prove $(n^5-n)$ is divisible by 5 by induction. What if I factor out a k? I believe that would give me $k^5 - 5$.
Apr 4	revised	Prove $(n^5-n)$ is divisible by 5 by induction. Fixed a mess.
Apr 4	asked	Prove $(n^5-n)$ is divisible by 5 by induction.
Apr 3	comment	If $b\mid ca$, then $b\mid a$. Is this true? Thanks. Everyone provided the answers I was looking for.
Apr 3	accepted	If $b\mid ca$, then $b\mid a$. Is this true?
Apr 3	asked	If $b\mid ca$, then $b\mid a$. Is this true?
Apr 3	awarded	Critic
Apr 3	accepted	If $a\mid b$ and $b\mid a$, then $a = b$ or $a = -b$. Is the converse true?