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 Feb 2 awarded Popular Question Dec 18 awarded Popular Question Nov 17 awarded Promoter Oct 13 awarded Tumbleweed Oct 6 asked Newton-Horner Method Example Nov 29 awarded Supporter Nov 25 asked How to know if it diverges or converges and finding the convergent value Dec 7 revised Analytic Geometry | Two Planes and a Angle | Two Solutions Added a missing D in the semilast formula. (Before the dots.) Dec 7 comment Analytic Geometry | Two Planes and a Angle | Two Solutions @Hans Lundmark, thanks for the explanation,now I get it, but after reading and reading Robin Chapman's statement, it seems that he is saying something that the problem says in it's legend, that is: "That the director numbers of the plane that I'm looking for are orthogonal to the line segment $P_1 P_2$ and that it forms a $60^\circ$ (\frac{\pi}{3}) angle with the known plane's normal... or Maybe I'm missing the point, did anyone look at what I already did? Dec 5 revised Analytic Geometry | Two Planes and a Angle | Two Solutions edited tags Dec 5 comment Analytic Geometry | Two Planes and a Angle | Two Solutions That's where I lost you, how can it be orthogonal at $60^\circ$, if in order to be orthogonal it must be a $90^\circ$, where should I use the $60^\circ$?, thank you for your reply and patience by the way. Dec 5 comment Analytic Geometry | Two Planes and a Angle | Two Solutions Well, your statement helped me find $A(C)$ using the perpendicularity theorem, but it just gives me a known fact: Director numbers of $l:[1,0,3]$ $$A(1)+B(0)+C(3)=0$$ we get: $$A=-3C$$ Dec 5 awarded Autobiographer Dec 5 comment Analytic Geometry | Two Planes and a Angle | Two Solutions @J.M. Hehe thanks I find it fun to use Tex (or LaTeX) syntax, love to see it render.. Dec 5 asked Analytic Geometry | Two Planes and a Angle | Two Solutions Dec 2 comment Equation of plane passing containing the intersection of other two planes, with a fixed distance to the origin. why no $\pm$ sign, the process of transforming from the general form to the normal form involves dividing by $r=\pm \sqrt{A^2+B^2+C^2}$, thats how we know that $$2=\frac{2(2k-1)}{\pm \sqrt{A^2+B^2+C^2}}$$ and the sign of $r$ is determined by the theorem I mention. Dec 2 comment Equation of plane passing containing the intersection of other two planes, with a fixed distance to the origin. @Arturo Magidin Yeah, corrected again the equation, sorry, it was a bit awkward writing in Tex, I hope I don't have any errors now, thank you for your patience. Dec 2 comment Equation of plane passing containing the intersection of other two planes, with a fixed distance to the origin. @Moron thank you for the welcome. Dec 2 revised Equation of plane passing containing the intersection of other two planes, with a fixed distance to the origin. Fixed some error in formulas. Dec 2 awarded Student