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Feb
18
accepted Differential Equation, finding where the solution is bounded
Feb
18
revised Differential Equation, finding where the solution is bounded
added 24 characters in body
Feb
18
asked Differential Equation, finding where the solution is bounded
Feb
18
accepted What is the particular solution of $y'' - 4y' + 3y = 2t + e^t$
Feb
18
asked What is the particular solution of $y'' - 4y' + 3y = 2t + e^t$
Feb
18
comment Differential Equation $y'' - 4y' + 4y = 0$
Then in what case will it has a form of $Ce^tcos(t)...Ce^tsin(t) $
Feb
18
accepted Differential Equation $y'' - 4y' + 4y = 0$
Feb
17
comment Differential Equation $y'' - 4y' + 4y = 0$
is it considered to have "repeated roots" if the roots are (r-2)(r+2)? (roots of 2 and -2). No right?
Feb
17
asked Differential Equation $y'' - 4y' + 4y = 0$
Feb
17
accepted Differential Equation $ (2x^2 + y^2)\,dx - xy \, dy = 0 $
Feb
17
comment Differential Equation $ (2x^2 + y^2)\,dx - xy \, dy = 0 $
In most problem (that I've seen so far) that are homogeneous, you set $ u =\frac{y}{x}$ , if I set $ u =\frac{x}{y}$ would that be a problem or would it just give you the same thing?
Feb
17
comment Differential Equation $ (2x^2 + y^2)\,dx - xy \, dy = 0 $
Now I have,$$y' = \frac{2x^2 + y^2}{xy} $$ $$ yy' = 2x + \frac{y^2}{x}$$
Feb
17
asked Differential Equation $ (2x^2 + y^2)\,dx - xy \, dy = 0 $
Feb
17
accepted Diff Eq. : Find an explicit solution of $y^2 - 1 = y'$
Feb
17
asked Diff Eq. : Find an explicit solution of $y^2 - 1 = y'$
Jan
25
asked Differential Equation Basic - please explain the detail of this step
Jan
25
comment Differential Equation: Using substitution $u(x)=y+x$, solve $\frac{dy}{dx} = (y+x)^2$
what if $ u(x) = y^3 $. what would be $ \frac{dy}{dx} $ in this case.
Jan
25
comment Differential Equation: Using substitution $u(x)=y+x$, solve $\frac{dy}{dx} = (y+x)^2$
thank you! I see i now
Jan
25
reviewed Approve Differential Equation: Using substitution $u(x)=y+x$, solve $\frac{dy}{dx} = (y+x)^2$
Jan
25
accepted Differential Equation $y' = \frac{ty(4-y)}{(1+y)}$