418 reputation
213
bio website
location United States
age
visits member for 1 year, 10 months
seen May 5 at 17:56

May
1
asked Differential Equation: Modifying Particular Solution
May
1
comment Inverse Laplace transform of $(2s+1)/(s^2 - 4s + 5)$
Thank you so much.
May
1
accepted Inverse Laplace transform of $(2s+1)/(s^2 - 4s + 5)$
May
1
asked Inverse Laplace transform of $(2s+1)/(s^2 - 4s + 5)$
May
1
accepted Finding fundamental set of solution of higher order differential equation
May
1
comment Finding fundamental set of solution of higher order differential equation
Sorry, I don't quite understand why I don't need to use Wronskian to conclude this. In which case then do I need to use the Wronskian to conclude that something is a fundamental set of solution? Thank you
May
1
asked Finding fundamental set of solution of higher order differential equation
May
1
accepted Differential equation: finding particular solution when the RHS is in form A/t
May
1
comment Differential equation: finding particular solution when the RHS is in form A/t
How to know when I need to apply the method of variation of parameter?
May
1
revised Differential equation: finding particular solution when the RHS is in form A/t
added 29 characters in body
May
1
asked Differential equation: finding particular solution when the RHS is in form A/t
Apr
30
accepted Differential Equation: Complex Eigenvalue
Apr
26
asked Differential Equation: Complex Eigenvalue
Apr
3
accepted Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$
Apr
3
comment Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$
"both $e^t$ and $te^t$" meaning the homogenous equation looks like $Ay'' - By' + Cy = e^t + te^t$, then the particular solution will look like $t^2e^t$, am I correct?
Apr
3
comment Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$
and if $te^t$ is already in the homogeneous solution, we will need to multiply by one more $t$ making it $t^2e^t$?
Apr
3
asked Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$
Apr
1
accepted Particular Solution of $y'' - 3y' - 4y = 3e^{2t}$
Apr
1
comment Particular Solution of $y'' - 3y' - 4y = 3e^{2t}$
Thank you. I feel ashamed that I did not see this.
Apr
1
asked Particular Solution of $y'' - 3y' - 4y = 3e^{2t}$