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	394 reputation	bio	website		visits	member for	7 months
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May 1	revised	Differential Equation: Modifying Particular Solution added 79 characters in body
May 1	comment	Differential Equation: Modifying Particular Solution Yes, but I the question here is just asking for the "form" of the particular solution.
May 1	reviewed	Approve suggested edit on Differential Equation: Modifying Particular Solution
May 1	asked	Differential Equation: Modifying Particular Solution
May 1	comment	Inverse Laplace transform of $(2s+1)/(s^2 - 4s + 5)$ Thank you so much.
May 1	accepted	Inverse Laplace transform of $(2s+1)/(s^2 - 4s + 5)$
May 1	asked	Inverse Laplace transform of $(2s+1)/(s^2 - 4s + 5)$
May 1	accepted	Finding fundamental set of solution of higher order differential equation
May 1	comment	Finding fundamental set of solution of higher order differential equation Sorry, I don't quite understand why I don't need to use Wronskian to conclude this. In which case then do I need to use the Wronskian to conclude that something is a fundamental set of solution? Thank you
May 1	asked	Finding fundamental set of solution of higher order differential equation
May 1	accepted	Differential equation: finding particular solution when the RHS is in form A/t
May 1	comment	Differential equation: finding particular solution when the RHS is in form A/t How to know when I need to apply the method of variation of parameter?
May 1	revised	Differential equation: finding particular solution when the RHS is in form A/t added 29 characters in body
May 1	asked	Differential equation: finding particular solution when the RHS is in form A/t
Apr 30	accepted	Differential Equation: Complex Eigenvalue
Apr 26	asked	Differential Equation: Complex Eigenvalue
Apr 3	accepted	Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$
Apr 3	comment	Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$ "both $e^t$ and $te^t$" meaning the homogenous equation looks like $Ay'' - By' + Cy = e^t + te^t$, then the particular solution will look like $t^2e^t$, am I correct?
Apr 3	comment	Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$ and if $te^t$ is already in the homogeneous solution, we will need to multiply by one more $t$ making it $t^2e^t$?
Apr 3	asked	Why is the particular solution of $y'' - 4y' +3y = e^t$ not in the form of $Ae^t$