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seen Oct 16 at 7:24

Nov
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awarded  Notable Question
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4
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Oct
27
awarded  Popular Question
Oct
16
accepted How many 6 digit numbers with 2 or 3 repetitions allowed
Oct
15
comment How many 6 digit numbers with 2 or 3 repetitions allowed
@calculus sorry for my bad English. I modified the question, maybe this time it is simpler to understand. From 2 repetitions, I tried to mean that every digit (0,..,9) can be used at most 2 times while forming the 6 digit number.
Oct
15
revised How many 6 digit numbers with 2 or 3 repetitions allowed
added 52 characters in body
Oct
15
revised How many 6 digit numbers with 2 or 3 repetitions allowed
added 54 characters in body
Oct
15
comment How many 6 digit numbers with 2 or 3 repetitions allowed
@CameronBuie yes both of them are true for their cases. sorry for the late reply
Oct
15
asked How many 6 digit numbers with 2 or 3 repetitions allowed
Jul
2
awarded  Curious
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awarded  Popular Question
Apr
8
comment Combinatorial explanation to following recurrence relation $a_n = 2 a_{n-1} + a_{n-2}$
@xen I did not say azimut's proof is not combinatorial. I just wanted to say it may not be what Xentius looking for according to his previous questions. But of course only one to confirm this is Xentius.
Apr
8
comment Combinatorial explanation to following recurrence relation $a_n = 2 a_{n-1} + a_{n-2}$
I guess what @Xentius meant by a combinatorial proof is not this. He seems to be looking for an answer like in this question he asked: math.stackexchange.com/questions/340905/…
Mar
19
comment Binomial formula for $(x+1)^{1/3}$ (related to Newton's binomial theorem)
@Xentius it's called gamma function.
Feb
19
revised How many zeros are there at $1000!$ in the base $24$
fixed two problematics
Feb
19
suggested approved edit on How many zeros are there at $1000!$ in the base $24$