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 Apr1 awarded Notable Question Nov16 awarded Notable Question Nov4 awarded Popular Question Oct27 awarded Popular Question Oct16 accepted How many 6 digit numbers with 2 or 3 repetitions allowed Oct15 comment How many 6 digit numbers with 2 or 3 repetitions allowed @calculus sorry for my bad English. I modified the question, maybe this time it is simpler to understand. From 2 repetitions, I tried to mean that every digit (0,..,9) can be used at most 2 times while forming the 6 digit number. Oct15 revised How many 6 digit numbers with 2 or 3 repetitions allowed added 52 characters in body Oct15 revised How many 6 digit numbers with 2 or 3 repetitions allowed added 54 characters in body Oct15 comment How many 6 digit numbers with 2 or 3 repetitions allowed @CameronBuie yes both of them are true for their cases. sorry for the late reply Oct15 asked How many 6 digit numbers with 2 or 3 repetitions allowed Jul2 awarded Curious Mar28 awarded Popular Question Jan6 awarded Notable Question Nov7 awarded Popular Question Sep28 awarded Yearling Aug11 awarded Popular Question Apr8 comment Combinatorial explanation to following recurrence relation $a_n = 2 a_{n-1} + a_{n-2}$ @xen I did not say azimut's proof is not combinatorial. I just wanted to say it may not be what Xentius looking for according to his previous questions. But of course only one to confirm this is Xentius. Apr8 comment Combinatorial explanation to following recurrence relation $a_n = 2 a_{n-1} + a_{n-2}$ I guess what @Xentius meant by a combinatorial proof is not this. He seems to be looking for an answer like in this question he asked: math.stackexchange.com/questions/340905/… Mar19 comment Binomial formula for $(x+1)^{1/3}$ (related to Newton's binomial theorem) @Xentius it's called gamma function. Feb19 revised How many zeros are there at $1000!$ in the base $24$ fixed two problematics