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| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 8 months |
| seen | Apr 9 at 8:21 | |
| stats | profile views | 43 |
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Apr 8 |
comment |
Combinatorial explanation to following recurrence relation $a_n = 2 a_{n-1} + a_{n-2}$ @xen I did not say azimut's proof is not combinatorial. I just wanted to say it may not be what Xentius looking for according to his previous questions. But of course only one to confirm this is Xentius. |
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Apr 8 |
comment |
Combinatorial explanation to following recurrence relation $a_n = 2 a_{n-1} + a_{n-2}$ I guess what @Xentius meant by a combinatorial proof is not this. He seems to be looking for an answer like in this question he asked: math.stackexchange.com/questions/340905/… |
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Mar 19 |
comment |
Binomial formula for $(x+1)^{1/3}$ (related to Newton's binomial theorem) @Xentius it's called gamma function. |
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Feb 19 |
revised |
How many zeros are there at $1000!$ in the base $24$ fixed two problematics |
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Feb 19 |
suggested | suggested edit on How many zeros are there at $1000!$ in the base $24$ |
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Dec 16 |
comment |
Proof about diameter of a set I guess this should be enough for a) Choose $x_n ∈ A_n$ , and show that the sequence $(x_n)$ satisfies the Cauchy condition. |
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Dec 16 |
comment |
For which x values, this series is convergent? @DonAntonio Thank you so much. It is a pleasure for me to be a member of the club. = ) |
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Dec 16 |
awarded | Teacher |
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Dec 16 |
revised |
For which x values, this series is convergent? deleted 10 characters in body |
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Dec 16 |
comment |
For which x values, this series is convergent? @DonAntonio Ops! you are both right. I edited my answer. |
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Dec 16 |
answered | For which x values, this series is convergent? |
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Dec 5 |
comment |
Limit proof of $a^n$ where |a|<1 yeah it is so simple. how could not I think that! :/ I guess I need to take a rest. thank you for your answer. |
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Dec 5 |
accepted | Limit proof of $a^n$ where |a|<1 |
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Dec 5 |
revised |
Limit proof of $a^n$ where |a|<1 added 3 characters in body |
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Dec 5 |
comment |
Limit proof of $a^n$ where |a|<1 @nikita2 you are right. I edited my question. |
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Dec 5 |
asked | Limit proof of $a^n$ where |a|<1 |
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Dec 5 |
awarded | Critic |
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Dec 4 |
accepted | A boundary point may not be an accumulation point proof |
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Dec 4 |
revised |
A boundary point may not be an accumulation point proof added 50 characters in body |
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Dec 4 |
asked | A boundary point may not be an accumulation point proof |
