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visits member for 2 years, 2 months
seen Apr 2 '13 at 6:22

Jul
2
awarded  Curious
Apr
2
comment Limit tends to infinity
Yeah, thanks. I guess the either the textbook is wrong or my memory failed. I wonder if this exists at first, but I remembered the answer was -3/2, so.
Apr
2
comment Trignometry - Cosine Formulae
thanks, i did the calculations and realized that
Apr
2
asked Limit tends to infinity
Mar
21
comment Trignometry - Cosine Formulae
thanks, ya, sine rules set limits on that also
Mar
21
comment Trignometry - Cosine Formulae
yes, sine law can solve it, just curious about how this happens?
Mar
21
asked Trignometry - Cosine Formulae
Dec
15
comment Evaluate $\lim\limits_{x \to \infty}\left (\sqrt{\frac{x^3}{x-1}}-x\right)$
I realized the necessity to apply square difference identity but just fail to apply that. Thanks!
Dec
15
asked Evaluate $\lim\limits_{x \to \infty}\left (\sqrt{\frac{x^3}{x-1}}-x\right)$
Oct
4
asked Find the range of $\cos B \cos C$ if $A+B+C = 180^\circ$ and $A=90^\circ$
Oct
4
comment Trigonometric identities changing sum to product
i don't get it, please elaborate, thanks
Oct
4
asked Trigonometric identities changing sum to product
Sep
29
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
ya, thanks, i got that now
Sep
29
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
Michael. Thank you for your advice, i will pay attention to how I typed latex now.
Sep
29
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
Abdulhaq. Which two functions are not the same?
Sep
28
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
verifying textbook now, since it is quite credible, i wonder if i made that wrong
Sep
28
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
i don't know if i made compound angles right, the original question is $$tanx+tan3x+\sqrt{3}tanxtan3x=tanxtan3x$$, same range for $$\theta$$, does it justifty 3 answers?
Sep
28
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
i count 4 if I solve for $$\theta$$? $$4\pi$$ is two revolution, the $$1^{st}$$ quadrant, $$3^{rd}$$ quadrant, $$5^{th}$$ quadrant, $$7^{th}$$ quardrant
Sep
28
comment Trigonometric equation $\tan4x=\sqrt 3,\qquad 0\leq x \lt \pi$
I am not following, $$\frac {20\pi}{6} = 3.3333333\pi \lt 4\pi$$?
Sep
28
awarded  Editor