network profile
| bio | website | |
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| location | ||
| age | ||
| visits | member for | 7 months |
| seen | Oct 16 '12 at 15:19 | |
| stats | profile views | 9 |
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Oct 16 |
awarded | Scholar |
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Oct 16 |
awarded | Supporter |
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Oct 16 |
accepted | Topic discussed in number theory today. |
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Oct 15 |
asked | Topic discussed in number theory today. |
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Sep 27 |
comment |
Congruences, elementary number theory I don't see how you get that last line. $(a-b)=(\alpha k+ \beta)m$ |
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Sep 27 |
comment |
Find all solutions to linear congruences I'm following most for part $(a)$ except for a couple things. Do we know there are only $5$ solutions because the $gcd(10,15)=5$? And also, what do you mean adding $3$ successively? Adding $3$ to $x=2$? So you're saying $x=5$ and $x=8$ are also solutions? |
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Sep 26 |
comment |
Find all solutions to linear congruences I think that is what I was trying to show for part $(a)$. I'm just not sure where to go afterward. |
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Sep 26 |
asked | Congruences, elementary number theory |
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Sep 26 |
comment |
Congruences, elementary number theory Sorry, yes meant to say $d|m$. |
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Sep 26 |
asked | Congruences, elementary number theory |
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Sep 26 |
awarded | Student |
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Sep 26 |
asked | Find all solutions to linear congruences |
