meta user
network profile
| bio | website | |
|---|---|---|
| location | Kleve, Germany | |
| age | 21 | |
| visits | member for | 7 months |
| seen | 2 hours ago | |
| stats | profile views | 172 |
First year student of pure mathematics at the Radboud University Nijmegen.
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5h |
comment |
How can one interpret a module as a vector space? (in a specific circumstance) what is meant by $p(T)(v)$ ? |
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May 10 |
comment |
jordans lemma application Is $\Gamma$ then still closed ? I think so but I am not sure :D |
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May 9 |
accepted | $\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. |
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May 9 |
comment |
$\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. Yeah. But the strange thing is, this is an exam question and before I was asked to prove the Jordan lemma in order to use it for this question. Indeed I have used $\sin \theta \geq 2 \theta /\pi$ on $[0,\pi /2]$ for the proof of the lemma. |
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May 9 |
comment |
$\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. I use this en.wikipedia.org/wiki/Jordan's_lemma |
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May 9 |
comment |
$\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. I am not sure if I can ignore $\theta = 0$. Otherwise the claim would follow since for $\theta \in (0,2\pi]$ we have that $\lim_{R \rightarrow \infty} \exp(-R^2 \sin 2 \theta) = 0$ for $R > 1$. Probably I can do this because leaving out a countable number of points from an integral doesn't change it |
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May 9 |
revised |
$\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. added 376 characters in body |
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May 9 |
comment |
$\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. Corrected it. My intentions was the limit as $R \rightarrow \infty$. |
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May 9 |
revised |
$\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. added 28 characters in body |
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May 9 |
asked | $\exp(i z^2)$ on $R e^{i \theta}$ with $\theta \in [0, \pi /4]$. |
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May 9 |
comment |
jordans lemma application what if $\theta = 0$ ? |
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May 4 |
asked | Convergence of Fourier series $\frac 1 {2i} \sum_{n \neq 0} \frac { \exp (inx)} n$ |
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Apr 17 |
comment |
Field extension of $\mathbb Q$ of degree 2 Ok. So then $a \in -\frac b 2 \pm \sqrt{ \frac {b^2} 4 -c }$ ? Can I just omit the constant term in $\mathbb Q$ and scale the term $b^2-4c$ such that this is in $\mathbb Z $ ? |
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Apr 17 |
asked | Field extension of $\mathbb Q$ of degree 2 |
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Apr 16 |
comment |
Graph with closed path of length $\leq 4$. Nice proof. The argumantation is thus: Assume that the vertices in $T_2$ are connected to exactly one vertice in $T_1$. Then $|T_2| \geq d(d-1)$ which gives us $d^2+1$ vertices which are too many. Thus there exists a vertice in $T_2$ which must be connected with more than one vertice in $T_1$. |
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Apr 16 |
accepted | Graph with closed path of length $\leq 4$. |
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Apr 16 |
asked | Graph with closed path of length $\leq 4$. |
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Apr 8 |
revised |
$k-$ Subsets of $\{1,\cdots,n\}$ with no consecutive integers added 1 characters in body |
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Apr 8 |
accepted | $k-$ Subsets of $\{1,\cdots,n\}$ with no consecutive integers |
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Apr 8 |
revised |
$k-$ Subsets of $\{1,\cdots,n\}$ with no consecutive integers added 113 characters in body |
