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May
15
comment Solve $(x^2 + 5)^2 - 15(x^2 + 5) + 54 = 0$
Try this: define a new variable z=x^2+5 and solve z^2-15z+54 using the quadratic formula. Then solve for x in terms of z.
May
12
comment Fractal Analysis
Perhaps the most fundamental way to compare two fractals would be by their dimension.