Kahel
Reputation
Next privilege 15 Rep.
Flag posts
5
Impact
~577 people reached

• 0 posts edited

# 30 Actions

 Dec21 awarded Tumbleweed Nov10 comment Balance and proportions Great! I was almost there but what I did was 1/2x + 1/2y = 1 and got stuck. . . Nov10 accepted Balance and proportions Nov10 asked Balance and proportions Oct29 comment Derive a formula of a specific curve Thanks Daniel!! Oct29 accepted Derive a formula of a specific curve Oct29 comment Derive a formula of a specific curve Great! Do you have any resources on how to come up whit a solution like this? I want to learn instead of spamming question on math.stackexchange :D Oct29 revised Derive a formula of a specific curve added 1 characters in body Oct29 asked Derive a formula of a specific curve Oct28 revised logarithmic function between two points added 234 characters in body Oct28 comment logarithmic function between two points Edit. I think I got it. . . Oct28 revised logarithmic function between two points deleted 78 characters in body Oct28 revised logarithmic function between two points deleted 78 characters in body Oct28 awarded Commentator Oct28 comment logarithmic function between two points edited but still in the dark :( Oct28 revised logarithmic function between two points added 201 characters in body Oct28 comment logarithmic function between two points you mean f(x)=a*log(x/c+b)? Oct28 asked logarithmic function between two points Oct12 comment Exponential equation and point on curve So X will be X = LOG Base{[logx0-x1(y0-y1)^x0/y0] * logx0-x1(y0-y1)} of Y Oct12 comment Exponential equation and point on curve Uhm I don't think I fail but I was seeking too much abstaction. I wanted something that cold be use for a exponential curve between two point A and B. If I'm not mistaken for a generic point (X,Y) on the exponential curve between (X0,Y0) and (X1,Y1) the function must be: Y = [logx0-x1(y0-y1)^x0/y0] * logx0-x1(y0-y1)^X