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visits member for 2 years, 3 months
seen Dec 16 '13 at 10:25

Dec
21
awarded  Tumbleweed
Nov
10
comment Balance and proportions
Great! I was almost there but what I did was 1/2x + 1/2y = 1 and got stuck. . .
Nov
10
accepted Balance and proportions
Nov
10
asked Balance and proportions
Oct
29
comment Derive a formula of a specific curve
Thanks Daniel!!
Oct
29
accepted Derive a formula of a specific curve
Oct
29
comment Derive a formula of a specific curve
Great! Do you have any resources on how to come up whit a solution like this? I want to learn instead of spamming question on math.stackexchange :D
Oct
29
revised Derive a formula of a specific curve
added 1 characters in body
Oct
29
asked Derive a formula of a specific curve
Oct
28
revised logarithmic function between two points
added 234 characters in body
Oct
28
comment logarithmic function between two points
Edit. I think I got it. . .
Oct
28
revised logarithmic function between two points
deleted 78 characters in body
Oct
28
revised logarithmic function between two points
deleted 78 characters in body
Oct
28
awarded  Commentator
Oct
28
comment logarithmic function between two points
edited but still in the dark :(
Oct
28
revised logarithmic function between two points
added 201 characters in body
Oct
28
comment logarithmic function between two points
you mean f(x)=a*log(x/c+b)?
Oct
28
asked logarithmic function between two points
Oct
12
comment Exponential equation and point on curve
So X will be X = LOG Base{[logx0-x1(y0-y1)^x0/y0] * logx0-x1(y0-y1)} of Y
Oct
12
comment Exponential equation and point on curve
Uhm I don't think I fail but I was seeking too much abstaction. I wanted something that cold be use for a exponential curve between two point A and B. If I'm not mistaken for a generic point (X,Y) on the exponential curve between (X0,Y0) and (X1,Y1) the function must be: Y = [logx0-x1(y0-y1)^x0/y0] * logx0-x1(y0-y1)^X