K. Stm.

1,749 reputation

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I'm an undergraduate student of mathematics in Germany, currently working on my bachelor thesis.

	1,749 reputation	bio	website		visits	member for	9 months
213 badges		location			seen	2 hours ago

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93 Revisions

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Jun 9	revised	Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate made mistake visible
Jun 7	revised	Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate added important piece of information
Jun 7	revised	Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate re-edited question to contain my addition while removing unicode symbols
Jun 6	revised	Chinese Remainder Theorem and matrix expanded answer
Jun 6	revised	Chinese Remainder Theorem and matrix added a requisite
Jun 6	revised	Chinese Remainder Theorem and matrix expanded answer
Jun 1	revised	In $ℤ/Nℤ$, which units are successors to zero divisors? pointed out misformulation
May 31	revised	In $ℤ/Nℤ$, which units are successors to zero divisors? formatting
May 28	revised	Representations of an integer as the sum of other integers clearified question, improved formatting
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? corrected mistakes
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? expanded answer
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? mistake correction
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? better formatting
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? added progress
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? added solution for x > 0
May 27	revised	Taylor expansion of $(1+x)^α$ to binomial series – why does the remainder term converge? added problem description, changed credits
May 15	revised	Does every smooth surjective function have a smooth right inverse? progress update
May 14	revised	Does every smooth surjective function have a smooth right inverse? mistake correction
May 14	revised	Does every smooth surjective function have a smooth right inverse? made the question more structured, specific and readable
May 12	revised	Proof: $f: A \to B$, if $f$ is bijection then $\forall a\in B \exists ! b\in A (f(b) = a) $ fixe typos