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I'm an undergraduate student of mathematics in Germany, currently working on my bachelor thesis.


Jun
10
comment What is a Hilbert space?
Don’t worry, even Hilbert himself was wondering.
Jun
9
revised Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
made mistake visible
Jun
9
comment Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
Aaaand I found a mistake: $\Im (\alpha z) ≤ 1/\Im (z)$ only implies $\Im (\alpha z) ≠ \Im (z)$ for $\Im (z) > 1$.
Jun
9
answered Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
Jun
8
comment We need to Prove the existence or define a function on $[a, b]$
… e.g. take the Weierstraß function.
Jun
7
revised Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
added important piece of information
Jun
7
revised Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
re-edited question to contain my addition while removing unicode symbols
Jun
7
comment Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
@vadim123 What’s the problem with unicode?
Jun
7
asked Proving those elliptic matrices in $\operatorname{SL}_2(ℤ)$ are not conjugate
Jun
6
comment Suppose a,b are real numbers, if a is rational and ab is irrational, then b is irrational (Is my solution correct?)
@GitGud What’s wrong with vimperator? Also, how are you rendering mathjax? Using SVG, right? As already told above, it works for me, too, when switching to SVG. You probably shouldn’t respond to this comment, as this gets too chatty. Now I upvoted your answer, because $-3$ seemed too harsh.
Jun
6
comment Suppose a,b are real numbers, if a is rational and ab is irrational, then b is irrational (Is my solution correct?)
@Git Gud : Me neither. Make a screenshot of how it’s supposed to look! Ah, it’s a thumbsup. I’m rendering with MathML, but using SVG it shows’s the thumbsup.
Jun
6
comment Suppose a,b are real numbers, if a is rational and ab is irrational, then b is irrational (Is my solution correct?)
The answer is Missingno.?
Jun
6
comment Suppose a,b are real numbers, if a is rational and ab is irrational, then b is irrational (Is my solution correct?)
Yes, it is, if you meant to prove that $b$ is ir-rational.
Jun
6
comment Chinese Remainder Theorem and matrix
Side question: How come CNT is an abbreviation for the Chinese Remainder Theorem?
Jun
6
revised Chinese Remainder Theorem and matrix
expanded answer
Jun
6
revised Chinese Remainder Theorem and matrix
added a requisite
Jun
6
suggested suggested edit on Chinese Remainder Theorem and matrix
Jun
6
revised Chinese Remainder Theorem and matrix
expanded answer
Jun
6
comment Chinese Remainder Theorem and matrix
@robjohn He didn’t mention $(a, b, N) = 1$. It’s clear if you look into the paper.
Jun
6
answered Chinese Remainder Theorem and matrix