Ayush Khemka
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 Jan17 awarded Nice Question Oct18 awarded Critic Oct9 comment If $\displaystyle x^2+\frac{1}{x^2}=66$ then what is the value of $\displaystyle\frac{x^2-1+2x}{x}$? +1 for the initial heads up. I just detailed your method to explain it step by step in my answer. Oct9 answered If $\displaystyle x^2+\frac{1}{x^2}=66$ then what is the value of $\displaystyle\frac{x^2-1+2x}{x}$? May26 answered What is $dx$ in integration? May20 awarded Famous Question Feb8 awarded Analytical Feb8 awarded Commentator Feb8 awarded Yearling Jul23 answered Differentiating $\tan\left(\frac{1}{ x^2 +1}\right)$ Jul23 comment Differentiate $\sin \sqrt{x^2+1}$with respect to $x$? Oh yes, and I think I used $x$ instead of $\sqrt {x^2+1}$. I'm so sorry for that! Jul23 comment Differentiate $\sin \sqrt{x^2+1}$with respect to $x$? The edits are accepted, they're right. But that was the way I was taught in school (back in the eleventh grade I guess), to work in functions rather than substitute variables, probably to make things easier for us back then. So, thank you everyone for your suggestions/reviews. Jul23 answered Differentiate $\sin \sqrt{x^2+1}$with respect to $x$? Jun18 awarded Notable Question May31 revised Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ deleted 2 characters in body May31 revised Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ added 7 characters in body May31 comment Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ oh well, ok i'll do that, think it has the same meaning though May31 revised Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ deleted 5 characters in body May31 comment Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ ok, i'll put it, thanks May30 answered Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$