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Dec
6
comment Is $\operatorname{null}(B) \subset \operatorname{null}(A)$?
We somehow have to prove that x satisfies Ax = 0, and thereby prove that x belongs to null(A) too?
Dec
6
asked Is $\operatorname{null}(B) \subset \operatorname{null}(A)$?
Sep
30
asked Eigenvalues, Eigenvectors and Eigendecomposition
Sep
27
awarded  Scholar
Sep
27
accepted Proof: Symmetric and Positive Definite
Sep
20
awarded  Supporter
Sep
20
comment Proof: Symmetric and Positive Definite
Thank you for the hints! It took a while for me to understand and form a proof. But eventually, it helped.
Sep
20
awarded  Student
Sep
20
asked Proof: Symmetric and Positive Definite