514 reputation
521
bio website notepins.wordpress.com
location India
age 18
visits member for 2 years, 3 months
seen 9 hours ago

Hey Stalkers!


I am Saharsh. A high school science student living in Gandhinagar. My basic interest includes Mathematics, Physics, Chemistry and Computer Science.

These are my academic fields and I am here for helping others over their questions and of course also for seeking some help from my side. If you think I can help you on any issue then please feel free to contact me. I am always right here on stackexchange! :)


Oct
24
suggested approved edit on process of $(a,b)R(c,d)\implies a\cdot b(b+c)=bc\cdot (a+d)$ being transistive relation..
Oct
24
comment Why non-real means only the square root of negative?
I of course know what's the difference. Imaginary is the subset of complex and it's not my doubt either. Please read the complete question with patience.
Oct
24
suggested rejected edit on process of $(a,b)R(c,d)\implies a\cdot b(b+c)=bc\cdot (a+d)$ being transistive relation..
Oct
24
comment Why non-real means only the square root of negative?
@Alan can you explain some examples in a bit detail. Your efforts will be appreciated. Thanks :)
Oct
24
comment Why non-real means only the square root of negative?
@JBKing Origin of Quaternion is something similar to square root of negative. Isn't it? Keep that function aside right now. I want to know it with some other functions.
Oct
24
comment How to solve system of Differential Equations with 1 independent and 3 dependent variables
I don't know whether it'll help or not but terms can be simplified to $$\frac{B''(t)}{B(t)}+\frac{F''(t)}{F(t)}+\frac{B'(t)F'(t)}{B(t)F(t)}=0 ------- (1)$$ $$\frac{A''(t)}{A(t)}+\frac{F''(t)}{F(t)}+\frac{A'(t)F'(t)}{A(t)F(t)}=0 ------ (2)$$ From (1), (2) and your third equation, $$2\frac{F''(t)}{F(t)}+\frac{B'(t)F'(t)+A'(t)F'(t)}{A(t)F(t)}=0$$
Oct
24
revised Why non-real means only the square root of negative?
edited title
Oct
24
asked Why non-real means only the square root of negative?
Oct
6
comment Prove the given condition from given two quadratic equation
Thank you very much. It really helped me a lot.
Oct
6
comment Prove the given condition from given two quadratic equation
Yep! Thank you very much. This was the very approach which I was seeking here, $$b^3+c^3+1-3bc=0$$ $$\implies (b+c+1)(b^2+c^2+1-bc-c-b)=0$$ now either $$b+c+1=0$$ or $$b^2+c^2+1=bc+b+c$$
Oct
6
revised the sum of $1-\frac{1}{5}+\frac{1}{9}-\frac{1}{13}+…$
title brushed up
Oct
6
asked Prove the given condition from given two quadratic equation
Oct
6
suggested approved edit on the sum of $1-\frac{1}{5}+\frac{1}{9}-\frac{1}{13}+…$
Sep
20
revised property of two numbers such that their exponential and product are the same
mathjax added
Sep
20
suggested approved edit on property of two numbers such that their exponential and product are the same
Sep
19
awarded  Yearling
Aug
17
revised Linear Equation in two variables problem
added 31 characters in body
Aug
17
accepted Figuring the function $f(x)$ from given information
Aug
17
accepted Why $2x$? Can't it be $x$?
Aug
17
accepted Derive the Quadratic Equation