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visits member for 1 year, 11 months
seen Apr 28 at 1:23

Jul
2
awarded  Curious
Mar
31
awarded  Popular Question
Sep
18
awarded  Yearling
Sep
17
comment Let $X$ be compact, separable, metric space. Then every bijection is a homeomorphism?
The problem doesn't state that $f$ is continuous, do you think this is a typo then?
Sep
17
asked Let $X$ be compact, separable, metric space. Then every bijection is a homeomorphism?
Sep
17
accepted If $X$ is separable then is the group of isometries on $X$ separable?
Sep
16
awarded  Nice Question
Sep
13
comment $X$ compact,metric space and $Y$ separable, complete metric space. Having trouble showing $C(X,Y)$ is separable.
For every $f \in C_{m,n}$ I would like to use denseness to choose an element of $Y$ that is close enough to each singleton of $f(X_m)$. Then find a function that maps some finite set to this image and then extend to a continuous function. My exact problems with this argument is that there could be uncountably many such $f$ and also how to extend a continuous function like that.
Sep
13
asked $X$ compact,metric space and $Y$ separable, complete metric space. Having trouble showing $C(X,Y)$ is separable.
Sep
11
accepted In a Baire space $X$, if an open set meets a nonmeager set, is the intersection nonmeager?
Sep
11
asked In a Baire space $X$, if an open set meets a nonmeager set, is the intersection nonmeager?
Sep
1
asked If $X$ is separable then is the group of isometries on $X$ separable?
Aug
31
accepted For a metric $d$ on a group $G$, why do $d$ and $d^{-1}$ generate the same topology.
Aug
30
comment For a metric $d$ on a group $G$, why do $d$ and $d^{-1}$ generate the same topology.
It must be a typo then, I will close the question soon. Thank you.
Aug
30
asked For a metric $d$ on a group $G$, why do $d$ and $d^{-1}$ generate the same topology.
Aug
24
accepted If we have an embedding $f:X \rightarrow A$, where $A \subset Y$, do we have to show $f^{-1}$ is continuous?
Aug
23
revised If we have an embedding $f:X \rightarrow A$, where $A \subset Y$, do we have to show $f^{-1}$ is continuous?
added 38 characters in body
Aug
23
comment If we have an embedding $f:X \rightarrow A$, where $A \subset Y$, do we have to show $f^{-1}$ is continuous?
@DanielRust: You are right, I found it. I didn't expect this. Thanks.
Aug
23
comment If we have an embedding $f:X \rightarrow A$, where $A \subset Y$, do we have to show $f^{-1}$ is continuous?
Yes, $X,Y$ are compact. I was thinking about that,...what does that do?
Aug
23
asked If we have an embedding $f:X \rightarrow A$, where $A \subset Y$, do we have to show $f^{-1}$ is continuous?