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| visits | member for | 9 months |
| seen | Oct 4 '12 at 7:55 | |
| stats | profile views | 8 |
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Oct 1 |
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Linear algebra of finite abelian groups (To be more explicit, your answer is no longer valid because the set of generators you produce for $H$ is an irredundant set of generators, but not a basis) |
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Oct 1 |
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Linear algebra of finite abelian groups (update) yes, {2,3} is both non-redundant and a basis for $\mathbb{Z}/6 \mathbb{Z}$. It is not a basis for $\mathbb{Z}$ since $6 \in (2) \cap (3)$. |
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Oct 1 |
answered | Constructing a basis for finite abelian groups |
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Oct 1 |
awarded | Commentator |
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Oct 1 |
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Linear algebra of finite abelian groups I have fixed my question with a different notion of "basis" for a finite abelian group. Sorry it took me so long. This is the question I really meant to ask. Does this make more sense to you? |
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Oct 1 |
revised |
Linear algebra of finite abelian groups added 215 characters in body |
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Sep 26 |
awarded | Teacher |
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Sep 26 |
accepted | Splitting exact sequences of finite abelian groups |
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Sep 26 |
answered | Splitting exact sequences of finite abelian groups |
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Sep 21 |
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Smallest pure subgroup containing a fixed subgroup I asked the same question on MO before you gave this argument, and it turns out that the answer is negative. Here is the link with a counterexample mathoverflow.net/questions/107768/… |
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Sep 21 |
revised |
Smallest pure subgroup containing a fixed subgroup added 1 characters in body |
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Sep 21 |
awarded | Editor |
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Sep 21 |
revised |
Smallest pure subgroup containing a fixed subgroup added 139 characters in body |
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Sep 21 |
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Smallest pure subgroup containing a fixed subgroup @Jack Schmidt Can you say something more on how you find this $h_1$? Moreover, how do we know that $g_2 \notin \langle h_1 \rangle$ ? |
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Sep 20 |
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Smallest pure subgroup containing a fixed subgroup @Hagen von Eitzen, the intersection of pure subgroups is not pure, so the title is a bit misleading. What I mean more precisely with "smallest" is explained in the question. |
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Sep 20 |
asked | Smallest pure subgroup containing a fixed subgroup |
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Sep 19 |
awarded | Scholar |
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Sep 19 |
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Splitting exact sequences of finite abelian groups Thanks! Yes, it seems to me that Chinese tells that GCD is equivalent to the existence of $k_i$ satisfying (1) and (2). |
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Sep 18 |
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Splitting exact sequences of finite abelian groups Thanks for your answer. Sorry but this looks to me just as the definition. Is it obvious that any of the three equivalent conditions proves (or disproves) the statement in my question? |
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Sep 18 |
awarded | Student |