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22h
answered What are all the automorphisms of $\mathbb{Q}(\sqrt{2})$?
22h
answered Is this still the smallest subfield of $\mathbb{C}$ that contains $\sqrt{d}$
2d
answered Help with partitions, equivalence classes, equivalence relations.
2d
answered Showing an equation has one positive root
2d
comment Alegebra- Function or NOT a function
The second one.
Sep
1
comment Three lines that intersect in a plane.
Are the lines perhaps given by equations of the form '$ax+by=c$'? Or what are your box symbols representing?
Sep
1
comment The sections of the projection $\bigsqcup_{i:I} X_i \rightarrow I.$
So, are you finally assuming that $X_i$'s are not empty? As you observed, it is needed to get any (global) section at all.
Sep
1
answered Exercise of algebra II
Aug
31
answered Set theory: Symmetric Difference properties.
Aug
31
answered Find two numbers knowing their sum and their difference
Aug
31
comment Find two numbers knowing their sum and their difference
$54$ $\,\!\,\!\,\!$
Aug
31
revised Understanding first part of dual basis proof
added 67 characters in body
Aug
31
answered Understanding first part of dual basis proof
Aug
31
answered Trouble with understanding dual space $V^{*}$.
Aug
31
answered Is it legal to define a function like this?
Aug
31
comment What is (if there is) the generic term for equalities and inequalities
Well, after the edit, I would still calmly use the term 'inequality' (or 'relation') for the generic name of possible input. Just introduce that you will use this word 'relation' in this sense.
Aug
31
comment What is (if there is) the generic term for equalities and inequalities
I guess you can rearrange everything (or multiply by $-1$ if preferred) to get the inequalities for the same direction. Also, an equation can be replaced to two inequalities. So, isn't simply inequality is what you are looking for?
Aug
31
comment some important proofs about adjoint operators
Do you mean $L^2(\Bbb R^n)$?
Aug
31
comment Can the order on an ordered, cancellative monoid be extended to its Grothendieck group?
Note that proving transitivity, we seem to need that the order is total: thus $m+y>n+y$ implies $m>n$ (else we would be left with the case $m\le n$ when $m+y\le n+y$).
Aug
30
comment Showing polynomials as products of roots
The hard piece is to show that every real (or complex) polynomial has a root in $\Bbb C$. For a first step, accept that and try to conclude by induction.