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Mar
21
comment Inconsitent general solutions of trigonometric equations
@corbah You are correct. Upon considering the negative values, they give the solutions for x that positive values didn't, e.g. $x = 210^\circ$. However, all the extra values, they'll just simply have to be rejected because they didn't fit the original equation of sin x = sin 30deg, correct?
Mar
21
comment Inconsitent general solutions of trigonometric equations
@Bernard fixed that technicality
Mar
21
revised Inconsitent general solutions of trigonometric equations
declare pi's value in degrees
Mar
11
asked Inconsitent general solutions of trigonometric equations
Nov
14
comment Proof: 1007 can not be written as the sum of two primes.
@EricTowers Wiki says that prime element of a commutative ring is an object satisfying certain properties similar to the prime numbers, so your answer that -2 is a prime number is incorrect?
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Apr
24
comment Proving that $\frac {\cos(π + x)\cos(-x)}{\cos(π-x)(\frac{π}{2}+x)} = \cot^2(x)$
nop. that's what the question is. I guess the question is wrong then.
Apr
24
revised Proving that $\frac {\cos(π + x)\cos(-x)}{\cos(π-x)(\frac{π}{2}+x)} = \cot^2(x)$
deleted 2 characters in body; edited title
Apr
24
comment Proving that $\frac {\cos(π + x)\cos(-x)}{\cos(π-x)(\frac{π}{2}+x)} = \cot^2(x)$
edited the question, had missed a term in denominator
Apr
24
comment Proving that $\frac {\cos(π + x)\cos(-x)}{\cos(π-x)(\frac{π}{2}+x)} = \cot^2(x)$
yes, edited the question
Apr
24
revised Proving that $\frac {\cos(π + x)\cos(-x)}{\cos(π-x)(\frac{π}{2}+x)} = \cot^2(x)$
deleted 2 characters in body; edited title
Apr
24
asked Proving that $\frac {\cos(π + x)\cos(-x)}{\cos(π-x)(\frac{π}{2}+x)} = \cot^2(x)$
Mar
25
comment coordinate geometry: finding the ratio in which a line segment is divided by a line
yeah, thats what I said
Mar
13
comment coordinate geometry: finding the ratio in which a line segment is divided by a line
oh. I think then it must be dividing the line segment externally, now I get it. I was confused since this was the first time when I encountered a negative ratio.